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3 years ago

9. Solve the equation. Check your solution, if possible. 1.5x + 1.3x = -8.4

Mathematics

2 answers:

Maksim231197 [3]3 years ago

6 0

Answer:

-3

Step-by-step explanation:

1.5x + 1.3x = -8.4

2.8x = -8.4

x=-3

NARA [144]3 years ago

5 0

<h2><u>Required Answer</u>:</h2>

As per the provided question, we have to find the value of x. So, we can easily find the value of x by transposition method.

$\sf \red { 1.5x + 1.3x = -8.4 }$

$\sf {\implies 2.8x = -8.4 }$

$\sf {\implies x =\dfrac{ -8.4 }{2.8}}$

$\sf {\implies x =\dfrac{ -84 \times \cancel{10} }{28 \times \cancel{10}}}$

$\sf {\implies x =\dfrac{ -84 }{28}}$

$\sf {\implies x = -3}$ $\purple {\bigstar}$

<h3>Let's check it too by verifying it! </h3>

<h2><u>Verification</u>:</h2>

Just substitute the value of x in L.H.S .

$\sf \red { 1.5x + 1.3x = -8.4 }$

Therefore

$\sf {\implies 1.5(-3) + 1.3(-3)= -8.4 }$

$\sf {\implies -4.5+ (-3.9)= -8.4 }$

$\sf {\implies -4.5-3.9= -8.4 }$

$\sf \purple {\implies -8.4= -8.4 }$

$\sf {\therefore L.H.S= R.H.S }$

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3 years ago

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4 years ago

at which values of x does the graph of f(x)=x^2-x-2/(x^2-1)(x^2-16) have a vertical asymptope? check all that apply

katen-ka-za [31]

Answer:

x = -4, 1, 4

Step-by-step explanation:

The function is given as:

f(x) = (x² - x -2)/[(x² - 1)(x² -16)]

We want to find the values of x where the graph will have vertical assymptote.

Vertical asymptotes are defined as vertical lines which correspond to the values of x that will make the denominator of a rational function to be zero.

Thus, to get the values of x that we will have vertical assymptotes, we have to equate the denominator to zero.

We have;

[(x² - 1)(x² -16)] = 0

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x = ±4

Values of x that give vertical assymptote are;

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3 years ago