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3 years ago

I need help this is timed i will mark u as brainliest.

Mathematics

2 answers:

dezoksy [38]3 years ago

4 0

Answer:

-8

Step-by-step explanation:

Irina-Kira [14]3 years ago

4 0

Answer:

I'm not very sure but it might be 12.

I'm very sorry if this is incorrect and I am going to vote myself 2 stars so you see this last

i-i dont deserve these points

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Simplify the expression x^5*x^7

goldenfox [79]

Answer:

x^12

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The equation y= 1/2 x +4 is graphed below.which equation would intersect this line at (4, 6)?

Anton [14]

Answer:

we have the equation y = (1/2)*x + 4.

now, any equation that passes through the point (4, 6) will intersect this line, so if we have an equation f(x), we must see if:

f(4) = 6.

if f(4) = 6, then f(x) intersects the equation y = (1/2)*x + 4 in the point (4, 6).

If we want to construct f(x), an easy example can be:

f(x) = y = k*x.

such that:

6 = k*4

k = 6/4 = 3/2.

then the function

f(x) = y= (3/2)*x intersects the equation y = (1/2)*x + 4 in the point (4, 6)

5 0

3 years ago

X² - 6x + 4 = 0 solve and show work. ...?

ycow [4]

The answer is 3 + √5 and 3 - √5.

This is quadratic equation: x² - 6x + 4 = 0
The general quadratic equation is ax² + bx + c = 0
Our equation can be rewritten: 1x² + (-6)x + 4 = 0
So, in our equation we have: a = 1, b = -6, c = 4

Now, x can be calculated using the formula: $x_{1,2}= \frac{-b+/- \sqrt{ b^{2}-4ac } }{2a}$
$x_{1,2} =\frac{-(-6)+/- \sqrt{ (-6)^{2}-4*1*4 } }{2*1} = \frac{6+/- \sqrt{36-16} }{2} = \frac{6+/- \sqrt{20} }{2} =\frac{6+/- \sqrt{4*5} }{2}= \\ 
=\frac{6+/- \sqrt{4}* \sqrt{5} }{2} =\frac{2*3+/- 2\sqrt{5} }{2}= \frac{2(3+/- \sqrt{5}) }{2} =3+/- \sqrt{5}$

From here:
$x_{1} =3+ \sqrt{5} \\ 
x_{2} =3- \sqrt{5}$

6 0

4 years ago

A certain jet can reach an altitude of 8000 ft while flying 16000 ft through the air. what is the angle of the elevation that th

irina1246 [14]

Answer:

27 degrees

Step-by-step explanation:

First, we can draw this out. Since the altitude is 8000, we can make that the height, and it goes 16000 feet through the air, that can be the length. I have drawn this out, as shown in the image. Note that when drawing, because the airplane is going up and forward, that path should represent the hypotenuse. The angle of elevation is the angle connecting the length and the path, as shown by the angle x in the picture.

We know than tan(x) = opposite/adjacent, so tan(x) here = 8000/16000 = 1/2. Then, arctan(1/2) =x = 27 degrees