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lisov135 [29]
3 years ago
5

I need help this is timed i will mark u as brainliest.

Mathematics
2 answers:
dezoksy [38]3 years ago
4 0

Answer:

-8

Step-by-step explanation:

np

Irina-Kira [14]3 years ago
4 0

Answer:

I'm not very sure but it might be 12.

I'm very sorry if this is incorrect and I am going to vote myself 2 stars so you see this last

i-i dont deserve these points

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The temperature is 50 degrees Fahrenheit. The temperature will decrease by 4 degrees F. each hour. Let h be the number of hours.
goblinko [34]

The correct answer choice is B

8 0
2 years ago
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Please thank youuu asap!!!!!!!!!!!!!!!!!
Vitek1552 [10]

All direct proportional graphs go through the origin (0,0). So this is where one point could go. The second point is found by going up 5 units and then to the right 3 units to get to (3,5)

<h3>Draw a straight line through (0,0) and (3,5) to graph</h3>

The equation of this line is y = (5/3)x

5 0
2 years ago
John has a piece of string that is 634 inches long, and Kerry has a piece of string that is 712
omeli [17]

Answer:

¾

Step-by-step explanation:

Length of Kerry string = 7(½) = 15/2

Length of John string = 6(¾) = 27/4

15/2 - 27/4

30 - 27/4

3/4

4 0
3 years ago
Read 2 more answers
work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
NISA [10]

Answer:

Step-by-step explanation:

Here is the complete question.

Dominique, Marco, Roberto , and John work for a publishing company. The company wants to send two employees to a statistics conference. To be fair, the company decides that the two individuals who get to attend will have their names drawn from a hat. This is like obtaining a simple random sample of size 2. (a) Determine the sample space of the experiment. That is, list all possible simple random samples of size n = 2. (b) What is the probability that Dominique and Marco attend the conference? (c) What is the probability that John attends the conference?  ​(d) What is the probability that John stays​ home?

Since there are four employees to select the two to send from. then for us to get the sample space for the experiment we need to merge all possible two employees and represent them as set.

Let D = Dominique, M = Marco, R = Roberto and J = John

a) The sample space for the experiment is the total number of possible outcomes that we can have. It is as given below

S = 4C2 = 4!/(4-2)!2! (Selecting 2 out of 4 employees)

Total sample space = 4!/2!2!

Total sample space = 4*3*2!/2!2

Total sample space = 12/2 = 6

The sample space are S = {DM, DR, DJ, MR, MJ, RJ}

b) Probability is the ratio of number of event to the sample space.

P = n(E)/n(S)

Given n(S) = 6

n(E) is the event of Dominique and Marco attending the conference.

E = {DM}

n(E) = 1

P(D and M) = 1/6

Hence  the probability that Dominique and Marco attend the conference is 1/6

c) For John to attend the conference, the event outcome will be given as;

E = {DJ, MJ, RJ}

n(E) = 3

n(S) = 6

Probability for John to attend the conference is 3/6 = 1/2

d) Probability that John stays at home = 1 - Prob (John attends the conference)

Probability that John stays at home = 1 - 1/2

Probability that John stays at home = 1/2

7 0
3 years ago
Please Help. 25 points. <br>​
vodomira [7]

Answer:

\boxed{x = 7, y = 9, z = 68}

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}

\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}

\boxed{\mathbf{ x = 7, y = 9, z = 68}}

4 0
3 years ago
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