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3 years ago

Pls help any 1 atleast!!!

Mathematics

1 answer:

sladkih [1.3K]3 years ago

8 0

Answer:

15. is B thats all I can do. srry

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If £1 is 11.15 swedish kronor how much is £500 exchanged for swedish kronor

Bess [88]

Answer:

5575 Swedish kronor

Step-by-step explanation:

<h2><u>Currency change</u></h2>

make use of the <em>cross multiplication method</em>

pound : Swedish kronor

1 : 11.15

500 : x

x = 500*11.15

= <u>5575 Swedish kronor </u>

3 0

4 years ago

Read 2 more answers

Help Please! What is the simplest form of the product? ^3 sqrt 4x^2 * ^3 sqrt 8x^7

iren2701 [21]

Answer:

$2x^3\sqrt[3]{4}$

Step-by-step explanation:

We have been given an expression $\sqrt[3]{4x^2} *\sqrt[3]{8x^7}$ and we are asked to find the product of our given expression.

Using exponent rule of power to powers $(a^{mn}=(a^m)^n)$ we can write $8x^7$ as $(2x^2)^3x$ and $4x^2=(2x)^2$ .

Upon substituting these values in our expression we will get,

$\sqrt[3]{4x^2} *\sqrt[3]{(2x^2)^3x}$

Using exponent rule $\sqrt[n]{x^m} =x^{\frac{m}{n}}$ we will get,

$\sqrt[3]{4x^2} *2x^2\sqrt[3]{x}$

Multiplying $\sqrt[3]{x}$ by $\sqrt[3]{4x^2}$ we will get,

$\sqrt[3]{4x^3} *2x^2$

Using exponent rule $\sqrt[n]{x^m} =x^{\frac{m}{n}}$ we will get,

$x\sqrt[3]{4}*2x^2$

$x*2x^2\sqrt[3]{4}$

$2x^3\sqrt[3]{4}$

Therefore, the simplest form of the product of our given expression will be $2x^3\sqrt[3]{4}$ .

5 0

4 years ago

Read 2 more answers

For each question, calculate the slope of a line that passes through the points

vovangra [49]

I think the answer is 2

8 0

3 years ago

Read 2 more answers

Which statement about population parameters and point estimates is false?

joja [24]

Answer: s is the population standard deviation. it is the square of the variance.

Step-by-step explanation:

i just did the quiz

8 0

3 years ago

Which graph represents the function f (x) = StartFraction 5 minus 5 x squared Over x squared EndFraction? On a coordinate plane,

trapecia [35]

9514 1404 393

Answer:

2. On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrants 1 and 4, and the other curve opens up and to the left in quadrants 2 and 3

Step-by-step explanation:

Technically, the curve is not a hyperbola. A hyperbola is of the form 1/x; this one is of the form 1/x².

The function can be simplified to ...

f(x) = 5/x² -5

which is a "hyperbola" with a vertical asymptote at x=0 and a vertical translation of -5 units to bring parts of it into the 3rd and 4th quadrants.

4 0

3 years ago