The first thing we must do for this case is to define a variable.
We have then:
x: number of years before the Russo-Japanese conflict began
We write now the inequality that models the problem.
We know that the conflict began in the year 1904, therefore, all the previous years are given by:
x <1904
Answer:
an inequality in terms of x and 1904 that is true only for values of x that represent years before the start of the Russo-Japanese War is:
x <1904
Answer: 1539.2nm
The space between molecule is going as X-1 function. That mean 1 molecule doesn't have space, 2 molecules have 1 space, 3 molecules have 2 space. Then 105 molecules will be will have 104 space.
Each space is 14.8nm, the total distance would be: 104 space x 14.8 nm/space= 1539.2nm
Answer:
The first option.
Step-by-step explanation:
In order to effectively simplify, you need to divide the side with the variable by a number that is less than or equal to the number. 3 goes into 36 twelve times.
3g = 36.
3g/3 = g
36/3 = 12
g = 12 when divided by 3.
Answer:
<h2>Hey , option B is correct ....</h2>
as two angles are equal
Answer:
A). Surface area = 222 cm²
Volume = 180 cm³
B). Surface area = 375 cm²
Volume = 360 cm³
C). % increase in surface area = 67.57%
% increase in volume = 100%
Step-by-step explanation:
In the figure attached base of a prism has been given.
A). Surface area of the prism = (Perimeter of the base of the prism) × height + 2(area of the base)
Perimeter of the base = 5 + 3 + 2 + 2 + 2 + 3 + 5 + 8
= 30
Area of the base = 8×5 - 2×2 = 36 cm²
Surface area of the prism = 30×5 + 2×(36)= 222 cm²
Volume of the prism = volume of the bigger prism - volume of the smaller prism cut off
= 8×5×5 - 2×2×5
= 200 - 20
= 180 cm³
B). Surface area of the prism if it's height is 10 cm,
Surface area = 30×10 + 2×(36) = 372 cm²
Volume of the prism = 8×5×10 - 2×2×10
= 400 - 40
= 360 cm³
C). Increase in surface area = 372 - 222 = 150 cm²
% increase in the surface area = 
= 67.57%
Increase in volume = 360 - 180 = 180 cm³
% increase in volume = 
= 100%
