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3 years ago

Rewrite to make true: The sequence 8,8,8,8,8, ... is neither arithmetic or geometric.

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

4 0

Answer:

8,8,-8,-8,8, ... is neither arithmetic nor geometric

Step-by-step explanation:

8,8,-8,-8,8, ...

This sequence is neither arithmetic nor geometric

We could also write

8,8,8,8,8, ... this is geometric since we multiply by 1 each time

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3 years ago

Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2

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Answer:

The solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

$y=6x-3\\y=x-2$

Solving:

Let:

$y=6x-3--eq(1)\\y=x-2--eq(2)$

Put value of y from equation 2 into equation 1

$y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}$

Now, put value of x in equation 2 to find value of y

$y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}$

So, the solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

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2 years ago

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Step-by-step explanation:

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3 years ago

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If k= t-5k and k= 4, what is the value of t? A) -28 B) -12 C) 12 D) 28

Gre4nikov [31]

Answer:

Step-by-step explanation:

k = t - 5k

→ Substitute in k

4 = t - 20

→ Add 20 to both sides

24 = t

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2 years ago

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