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bazaltina [42]
3 years ago
6

Rewrite to make true: The sequence 8,8,8,8,8, ... is neither arithmetic or geometric.

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
4 0

Answer:

8,8,-8,-8,8, ... is neither arithmetic nor geometric

Step-by-step explanation:

8,8,-8,-8,8, ...

This sequence is neither arithmetic nor geometric

We could also write

8,8,8,8,8, ... this is geometric since we multiply by 1 each time

You might be interested in
Simplify sin(tan^(-1)x)
AnnZ [28]
Sin (tan^(-1)X)
Sin (1/tan X)
Sin (1/1 / tan X/1)
Tan X = sin X/cos X

Sin (1/1 / sin X/cos X)
Sin (1/1 • cos X/Sin X)
Sin (cos X/sin X )
Cos X.

I believe the correct answer is cos X.
4 0
3 years ago
Marcus borrowed 9000 from his bank to buy a car. The bank charged him a simple interest rate of 1.25%. By the time he paid back
snow_lady [41]

Answer:

2.5 years

Step-by-step explanation:

Given data

P=9000

r= 1.25%

A= 9281.25

The simple interest expression is given as

A=P(1+rt)

substitute

9281.25= 9000(1+0.0125*t)

9281.25=9000+112.5t

collect like terms

9281.25-9000=112.5t

281.25= 112.5t

t= 281.25/112.5

t= 2.5

Hence the time is 2.5 years

7 0
3 years ago
Pls help I need the answer
alexandr402 [8]

Answer:

The first choice.

8 0
2 years ago
Read 2 more answers
the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
3 years ago
I don't know how to do this problem.....please help
Lemur [1.5K]
I hope this helps you

5 0
3 years ago
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