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Papessa [141]
3 years ago
15

It takes Mia 49 minutes to complete 14 homework problems on average, how long did it take to solve each problem

Mathematics
1 answer:
hoa [83]3 years ago
6 0

Answer: 3.5 minutes per problem

Step-by-step explanation: To find the average divide 49 by 14 to get 3.5.

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Mark wants to paint a mural. He has 1 1/8 gallons of yellow paint, 1 1/9 gallons of green paint, and 7/8 gallon of blue paint. M
Sauron [17]

Here is the set up:

(3/4)[(11/8) + (11/9) + (7/8)]

Do the math to find your answer.

3 0
3 years ago
Read 2 more answers
What is the coefficient in the expression 10x + 8 I need help
koban [17]

Answer:

10

Step-by-step explanation:

A coefficient is a multiplicative factor. Whatever is in front of the variable is a coefficient

5 0
3 years ago
Collin is building a deck on the back of his house. He has enough lumber for the deck to be 144 square feet. The length should b
joja [24]
Width = x
length = x+10

Area of deck = 144 square feet

Area = length * width

144 = x(x+10)

Solving for x in a quadratic:

x²+10x = 144
x²+10x-144 = 0

Factor:
(x+18)(x-8) = 0

Solving for x:
x = 8, x = -18

Dimensions cannot be negative, therefore x = 8, only.

Length = x + 10
Length = 18

Width = 8
4 0
3 years ago
I need help with these 2 questions!! please 20 points!!!
bezimeni [28]

9514 1404 393

Answer:

  1. 45 cm²
  2. 38 cm²

Step-by-step explanation:

The conventional way to work these problems is to make use of the formulas for areas of a triangle, rectangle, and semicircle. If you've used these formulas for a while, you recognize that they give you certain relationships that may make these problems easy to do mentally.

__

1. The area of a triangle is half the product of height and width, so is equivalent to the area of a rectangle either half as high, or half as wide. We note that the width of the sail is 5 cm, so half that is 2.5 cm--exactly the same as the height of the boat's hull. That means we can add the height of the sail to the length of the boat, and the total area can be considered to be the same as that of a rectangle that is

  2.5 cm high × (12 cm + 6 cm) long = (2.5)(18) cm² = 45 cm²

__

2. The usual formula for the area of a circle is ...

  A = πr²

When expressed in terms of diameter, this becomes ...

  A = π(d/2)² = (π/4)d²

Then the area of a semicircle is half that, or (π/8)d². This is equivalent to the area of a rectangle that is "d" wide and "π/8·d" high. That is, the approximate area of the semicircle is that of a rectangle 4 cm high by (π/8·4 cm) = π/2 cm wide. In other words, the semicircle effectively adds π/2 cm to the left end of the 6 cm central rectangle of the figure.

As discussed above, the area of a triangle is equivalent to the area of a rectangle half as high. In this figure, the triangle is 10-6 = 4 cm wide, so can be considered to contribute 4/2 = 2 cm to the right end of the 6 cm central rectangle.

If we consider π ≈ 3, then the approximate area of the figure is ...

  (4 cm)(3/2 cm + 6 cm + 2 cm) = (4)(9.5) cm² = 38 cm²

__

The exact value is 4(8+π/2) = 32+2π ≈ 38.283 cm².

7 0
2 years ago
Find the maximum and minimum values of f(x,y) = 8x+y for the polygonal convex set having vertices at (0, 0), (4, 0), (3, 5), (0,
Helen [10]
F(x,y)=8x+y

This means, f is a function where we plug in pairs of numbers.
then, f calculates the first number times 8, to which it then adds the second number we plugged.

let's calculate f for the vertices:

f(0,0)=8*0+0=0+0=0

f(4, 0)=8*4+0=32+0=32

f(3, 5)=8*3+5=24+5=29

f(0, 5)=8*0+5=0+5=5

the maximum value of f is 32
the minimum value of f is 0
4 0
3 years ago
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