Solve x+y= -1 x - y = -7 using elimination.

This is my question

Talja [164]

Answer/Step-by-step explanation:

∆ABC is similar to ∆CDE. Therefore, the ratio of their corresponding sides are proportional.

This,

$\frac{DE}{AB} = \frac{DC}{AC}$

$\frac{4}{3} = \frac{x + 3}{x + 1}$

Solve for x

$4(x + 1) = 3(x + 3)$

$4x + 4 = 3x + 9$

$4x + 4 - 4 = 3x + 9 - 4$

$4x = 3x + 5$

$4x - 3x = 3x + 5 - 3x$

$x = 5$

Use the value of x to find AC and DC

$AC = x + 1 = 5 + 1 = 6$

$DC = x + 3 = 5 + 3 = 8$

4 0

3 years ago

9 more than a number is 58. write and solve an equation to determine the number (writing the equation is required)

Stels [109]

$58 - 9 = 49$

5 0

3 years ago

Drag each number to the correct location on the table. Each number can be used more than once, but not all numbers will be used.

muminat

Answer:

1. $12x^2-13.4x-11$

- Degree: 2

- Number of terms: 3

2. $7x^3+168$

- Degree: 3

- Number of terms: 2

3. $9x^4-9$

- Degree: 4

- Number of terms: 2

Step-by-step explanation:

For this exercise you need to remember the multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-$

1. Given:

$(4x + 2.2)(3x - 5)$

Apply the Distributive property:

$=12x^2+6.6x-20x-11$

Add the like terms:

$=12x^2-13.4x-11$

You can idenfity that:

- Degree: 2

- Number of terms: 3

2. Given:

$(-304 +503 - 12) + (7x^3 - 25 + 6)$

Add the like terms:

$=187 + 7x^3 - 25 + 6=7x^3+168$

You can idenfity that:

- Degree: 3

- Number of terms: 2

3. Given:

$(3x^2 - 3)(3x^2 + 3)$

Apply Distributive property:

$=9x^4-9x^2+9x^2-9$

Add the like terms:

$=9x^4-9$

You can idenfity that:

- Degree: 4

- Number of terms: 2

8 0

3 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

The value of\[\left( 1-{1\over3} \right)\left( 1-{1\over4} \right)\left( 1-{1\over5} \right)....\left( 1-{1\over n} \right)\]is

Oliga [24]

Example 1

verbose explicit high3 plus 4 cross 2 minus minus 2 equals 3 plus 8 plus 2 equals 1 3verbose explicit high semantics3 plus 4 times 2 minus negative 2 equals 3 plus 8 plus 2 equals 13verbose explicit high semantics high3 plus 4 times 2 minus negative 2 equals 3 plus 8 plus 2 equals 13

For most fractions, the beginning is indicated with "start fraction", the horizontal line is indicated with "over", and the end of the fraction is indicated by "end fraction". For the semantic interpretation, most numeric fractions are spoken as they are in natural speech. Also if a number is followed by a numeric fraction, the word "and" is spoken in between.

6 0

3 years ago