Ask question

Ask question

All categories

2 years ago

11

Flip a coin 4 times and calculate the experimental probability of the coin landing heads up. Flip a coin 4 more times to increas

e the total number of trials to 8. What is the experimental probability of the coin landing heads up?

2 answers:

Allushta [10]2 years ago

8 0

Answer:

3/4 and 5/8

Step-by-step explanation:

MaRussiya [10]2 years ago

7 0

Answer:

0.35 Not sure

Step-by-step explanation:

You might be interested in

Dylan buys 3.2 pounds of grapes for $2.56. What is the price per pound of the grapes?

Alona [7]

Answer:

$0.64/lb

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

A baseball team wants a pitcher no more 150 innings during a season. So far, the pitcher has pitched <img src="https://tex.z-dn.

butalik [34]

Answer:

C. 6 because any answer besides that is too low or too high.

Step-by-step explanation:

110.25 pitches so far- 150 at max. 5.75 pitches per game.

4: 4x5.75 = 23

110.25 + 23 = 133.25

5. 5x5.75 = 28.75

110.25 + 28.75 = 139

6: 6x5.75 = 34.5

110.25 + 34.5 = 144.75

7: 7x5.75 = 40.25

110.25 + 40.25 = 150.50 > which rounds up to 151

5 0

2 years ago

Given the data shown below, which of the following is the best approximation of the coefficient of determination (r^2)

HACTEHA [7]

The coefficient of determination can be found using the following formula:

$r^2=\mleft(\frac{n(\sum ^{}_{}xy)-(\sum ^{}_{}x)(\sum ^{}_{}y)}{\sqrt[]{(n\sum ^{}_{}x^2-(\sum ^{}_{}x)^2)(n\sum ^{}_{}y^2-(\sum ^{}_{}y)^2}^{}}\mright)^2$

Using a Statistics calculator or an online tool to work with the data we were given, we get

So the best aproximation of r² is 0.861

8 0

10 months ago

Find the sum of the given arithmetic series. 14 + 28 + 42 + 56 + ... + 280

cricket20 [7]

14 + 28 + 42 + 56 + … 280

= 14 (1 + 2 + 3 + 4 + … + 20)

= 14 × 20 × 21 / 2

= 2940

where we use the well-known identity,

$\displaystyle \sum_{i=1}^ni = 1 + 2 + 3 + \cdots + n = \dfrac{n(n+1)}2$

6 0

2 years ago

Polygon ABCD is dilated, rotated, and translated to form polygon A′B′C′D′. The endpoints of AB are at (0, -7) and (8, 8), and th

Anton [14]

Rotation and translation are rigid transformations, they don't change figure sizes. Dilation change figure sizes increasing or decreasing them by scale factor.

First, find AB and A'B' by the formula:

$AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}= \sqrt{(8-0)^2+(8-(-7))^2}=\sqrt{8^2+15^2}=\sqrt{64+225}=\sqrt{289}=17,\\ \\A'B'=\sqrt{(x_{B'}-x_{A'})^2+(y_{B'}-y_{A'})^2}= \sqrt{(2-6)^2+(1.5-(-6))^2}=\sqrt{4^2+7.5^2}=\sqrt{16+56.25}=\sqrt{72.25}=8.5.$

As you can see AB=2A'B'. This means that the segment AB was decreased twice to form segment A'B'. Then the scale factor is 1/2.

8 0

2 years ago