All categories

3 years ago

Kayla lives 5 2/4 miles from her dad’s house. What fraction greater than one can you write 5 2/4?

Mathematics

1 answer:

mihalych1998 [28]3 years ago

8 0

6 3/4 I think is a possible answer

You might be interested in

I really need help with this problem...."Arliss has two pieces of carpet runner. One is 2 1/3 yards long and the other is 3 1/3

KIM [24]

2 (1/3) + 3 (1/3) is easy to add
2 + 3 = 5
(1/3) + (1/3) = (2/3)
So, it equals 5 (2/3)
She needs 10 - 5 (2/3) more
= 4 (1/3)

7 0

3 years ago

The value of 2 in 2784 is Times the value of 2 in 7283

Vinvika [58]

Ten times the value of 2 in 7283

6 0

2 years ago

Find a 95% confidence interval for the mean auditory response time for subjects with a visual response time of 200 ms. The 95% c

Sveta_85 [38]

Answer:

hello your question is incomplete attached below is the complete question

answer : ( 184.019 , 206.219 )

Step-by-step explanation:

The 95% confidence interval for the mean auditory response time for subjects with a visual response time of 200 ms can be calculated using this relationship below

y = Bo + B1 ( 200 ) = 195.118621 , sy =

hence a 95% confidence interval = 195.118621 ± 2.306( 4.813492) i.e. ( 184.019 , 206.219 )

attached below is the remaining part the solution

6 0

2 years ago

Suppose that the population of a town Increases by 3% each year. the population of the town today is 25,000

jolli1 [7]

Answer:

The population of town after 1 year is 25,750 .

Step-by-step explanation:

Given as :

The rate of increase in the population of town each year = 3 %

The initial population of town = 25,000

Let the population of town after one year = x

So,

The population after n year = initial population × $(1+\dfrac{\textrm rate}{100})^{\textrm n}$

Or, The population after 1 year = 25,000 × $(1+\dfrac{\textrm 3}{100})^{\textrm 1}$

Or, The population after 1 year = 25,000 × $(1.03)^{1}$

Or, The population after 1 year = 25,000 × 1.03

∴ The population after 1 year = 25,750

Hence The population of town after 1 year is 25,750 . Answer

3 0

3 years ago

If 60% of the students in your class like Burger King, how many students are in your class if 15 students like Burger King?

zloy xaker [14]

Answer:

Step-by-step explanation:

Let x be the number of students in the class

15 is 60% of x

60% of x can be written as 0.6x

15 = 0.6x

Divide by 0.6 on both sides

25 = x

There are 25 students in the class

Hope this helps :)

8 0

2 years ago