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3 years ago

Evaluate the expression. (65+ (1/5 x 5) + 6) Divided by 9

Mathematics

1 answer:

Rzqust [24]3 years ago

8 0

Answer:

Step-by-step explanation:

$\frac{65+(\frac{1}{5} *5)+6}{9} \\\\\frac{65+1+6}{9} \\\\\frac{72}{9} \\\\8$

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What is the area of the shaded region

xeze [42]

Given:

Given that the radius of the circle is 12 cm.

The length of the rectangle is 11 cm.

The width of the rectangle is 5 cm.

We need to determine the area of the shaded region.

Area of the rectangle:

The area of the rectangle can be determined using the formula,

$A_1=length \times width$

Substituting the values, we have;

$A_1=11\times 5$

$A_1=55 \ cm^2$

Thus, the area of the rectangle is 55 square cm.

Area of the circle:

The area of the circle can be determined using the formula,

$A_2=\pi r^2$

Substituting r = 12, we have;

$A_2= (3.14)(12)^2$

$A_2=452.16 \ cm^2$

Thus, the area of the circle is 452.16 square cm.

Area of the shaded region:

The area of the shaded region can be determined by subtracting the area of the rectangle from the area of the circle.

Thus, we have;

Area = Area of the circle - Area of the rectangle.

Substituting the values, we have;

$Area=452.16-55$

$Area=397.16 \ cm^2$

Thus, the area of the shaded region is 397.16 square cm.

6 0

2 years ago

Leila started a savings account to buy a new bike. She started with some money her grandmom gave her and added the same amount e

zalisa [80]

The answer to this question is:
Leila started a savings account to buy a new bike. She started with some money her grandmom gave her and added the same amount each week from her babysitting earnings. What is the dependent variable?
D-the amount in the savings account when she finishes saving

7 0

3 years ago

An article reported on the results of an experiment in which half of the individuals in a group of 60 postmenopausal overweight

slavikrds [6]

Answer:

Step-by-step explanation:

From the given information:

Let's first compute the null and alternative hypothesis

Null hypothesis:

$\mathbf{H_o: \mu_1-\mu_2=1}$

Alternative hypothesis:

$H_a :\mu_1 -\mu_2 > 1$

The number of samples is half in a group of 60

i.e

$n_1=n_2 = 30$

the sample mean for sample 1 $\overline x_1$ = 5.7

the standard deviation for sample 1 $s_1$ = 3.1

the sample mean for sample 2 $\overline x_2$ = 3.9

the standard deviation for sample 2 $s_2$ = 2.7

degree of freedom for this test can be computed by using the formula:

$df = \dfrac{\begin {pmatrix} \dfrac{s_1^2}{n_1} + \dfrac{s^2_2}{n_2} \end {pmatrix}^2 } {\dfrac{ (\dfrac{s_1^2}{n_1}^2)}{ n_1-1} + \dfrac{ (\dfrac{s_2^2}{n_2}^2)}{ n_2-1} }$

$df = \dfrac{\begin {pmatrix} \dfrac{3.1^2}{30} + \dfrac{2.7^2}{30} \end {pmatrix}^2 } {\dfrac{ \begin {pmatrix} \dfrac{3.1^2}{30} \end {pmatrix}^2}{ 30-1} + \dfrac{ \begin {pmatrix} \dfrac{2.7^2}{30} \end {pmatrix}^2}{ 30-1} }}$

df = 114.68

The test statistics can be computed as follows:

$t = \dfrac{ \overline x_1 -\overline x_2- (\mu_1 -\mu_2)}{\sqrt{ \dfrac{s_1^2}{n_1} +\dfrac{s_2^2}{n_2} }}$

$t = \dfrac{ 5.7-3.9- (1)}{\sqrt{ \dfrac{3.1^2}{30} +\dfrac{2.7^2}{30} }}$

t = 1.07

Using the level of significance of 0.1, the P-value for the test statistics at the df of 114.68 is:

P-value = 0.143

Decision rule: To reject the null hypothesis if the level of significance is greater than the p-value.

Conclusion: We fail to reject the null hypothesis because the p-value is greater than the level of significance at 0.1.

Thus, it appears that the true average weight loss for the vegan diet does not exceeds that for the control diet by more than 1 kg.

8 0

3 years ago

Write a thesis statement for your argument aginst online learning

Marina86 [1]

Answer:

Online Learning is bad because it can cause social Isolation, it requires strong self-motivation and time management skills , Lack of communication skill development in online students and cheating prevention during online assessments is very complicated.

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

What is the lmc for 6 and 14

lana [24]

Answer:

The Lcm is 42/

Step-by-step explanation:

Least common multiple (LCM) of 6 and 14 is 42.

Hope that helped.

5 0

2 years ago

Read 2 more answers