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3 years ago

6

On parallelogram ABCD. Make a point where the diagonals intersect, and label it E. Measure and record the lengths of the four li

ne segments you just created.

1 answer:

Elan Coil [88]3 years ago

6 0

Answer:

i dont know

Step-by-step explanation:

You might be interested in

The lengths of brook trout caught in a certain Colorado stream are normally distributed with a mean of 14 inches and a standard

mezya [45]

Answer:

0.6563 or 65.63% of brook trout caught will be between 12 and 18 inches

Step-by-step explanation:

Mean trout length (μ) = 14 inches

Standard deviation (σ) = 3 inches

The z-score for any given trout length 'X' is defined as:

$z=\frac{X-\mu}{\sigma}$ e interval

For a length of X =12 inches:

$z=\frac{12-14}{3}\\z=-0.6667$

According to a z-score table, a score of -0.6667 is equivalent to the 25.25th percentile of the distribution.

For a length of X =18 inches:

$z=\frac{18-14}{3}\\z=1.333$

According to a z-score table, a score of 1.333 is equivalent to the 90.88th percentile of the distribution.

The proportion of trout caught between 12 and 18 inches, assuming a normal distribution, is the interval between the equivalent percentile of each length:

$P(12\leq X\leq 18) = 90.88\% - 25.25\%\\P(12\leq X\leq 18) = 65.63\%$

8 0

3 years ago

List the elements of the set given below.

svetoff [14.1K]

Answer:

The set = {1, 2, 3, 4, 5}

Step-by-step explanation:

Let us explain how to solve this question

∵ The set = {x : x is a digit in the number 241,532)

→ That means the elements of the set are the digits of the given number

∴ The elements in this set are the digits of the number 241,532

∵ The digits of the number 241,532 are 2, 4, 1, 5, 3, 2

→ In any set of numbers,

Do not repeat any number
Arrange the numbers

∴ The elements of the set are 1, 2, 3, 4, 5

∴ The set = {1, 2, 3, 4, 5}

8 0

3 years ago

A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.

olga55 [171]

We know that:

$(x-a)^2+(y-b)^2=r^2$

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}$

and all we have to do is solve it for a, b and r.

There will be:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\
$

From equations (II) and (III) we have:

$\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}$

and from (I) and (II):

$\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}$

Now we can easly calculate a and b:

$\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}$

Finally we calculate $r^2$ :

$a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}$

And the equation of the circle is:

$(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}$

7 0

3 years ago

If the diameter of a circle has endpoints A (7,2) and B (-1,8), where is the center?

docker41 [41]

In the middle: x-coordinate= {7-(-1)}/2= 4 y-coordinate= (8-2)/2= 3 So centre is (4,3)

3 0

3 years ago

Read 2 more answers

GaryK [48]

Answer:

$B_2=4\pi r^2$

see the explanation

Step-by-step explanation:

we know that

The area of the base of a cylinder is given by the formula

$B=\pi r^{2}$

where

r is the radius of the circular base

If the radius is doubled

then

$r=2r$

The new base area is

$B_2=\pi (2r)^{2}$

$B_2=4\pi r^2$

so

$B_2=4B$

therefore

The new area of the base is 4 times the area of the original base

7 0

3 years ago