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Kay [80]
3 years ago
5

What are the possible values of x in x2 + 3x + 3 = 0?

Mathematics
2 answers:
In-s [12.5K]3 years ago
5 0
x^2 + 3x + 3 = 0 

Apply \ the \ Quadratic \ Formula 


Given \ the  \ general \ form \ ax^2+bx+c=0there \ exists \ two \ solutions \ where: a=1, b=3 \ and \ c=3 

x= \dfrac{-3+ \sqrt{3i}}{2}, \dfrac{-3- \sqrt{3i} }{2} 


stealth61 [152]3 years ago
3 0
Hello,

x^2+3x+3=0\\

\Delta=9-4*3=-3\\

x= \dfrac{-3-i*\sqrt{3}}{2} \ or\ x= \dfrac{-3+i*\sqrt{3}}{2} \\


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Step-by-step explanation:

7+7+7+7

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Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

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Choose a non-integer between 0 and 1
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I don't think there is one because integers are whole numbers.
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