Answer:
B
Step-by-step explanation:
I checked it and it’s right I hope this helps!!
A is the correct answer i'm pretty sure
Answer:
Sorry but your question is not too explanatory but I sure hope this helps
Answer:
hi there ☺️
Here we will use algebra to find three consecutive integers whose sum is 345. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 345. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 345
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 345
3X + 3 = 345
3X + 3 - 3 = 345 - 3
3X = 342
3X/3 = 342/3
X = 114
Which means that the first number is 114, the second number is 114 + 1 and the third number is 114 + 2. Therefore, three consecutive integers that add up to 345 are 114, 115, and 116.
114 + 115 + 116 = 345
We know our answer is correct because 114 + 115 + 116 equals 345 as displayed above.
Step-by-step explanation:
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Answer:
Step-by-step explanation:
<u>As per diagram:</u>
- ∠NXY ≅ ∠XYZ as alternate interior angles since XN and YN are parallel and XY is transversal
- m∠XYZ = m∠XZY = 63° since ΔXYZ is isosceles
<u>Find the measure of ∠YXZ:</u>
- m∠YXZ = 180° - 2*63° = 54°
<u>Find the bearing of Z from X:</u>
- m∠NXZ = m∠NXY + m∠YXZ = 63° + 54° = 117°
