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aleksley [76]
3 years ago
15

Sallie makes candles using different scents. She sells each candle for $8 on her website. She writes the equation y = 8x to dete

rmine how much money, y, she earns from selling x candles. What does the independent variable represent in this situation? A The number of scents B The number of candles Sallie sells C The cost of each candle Sallie sells D The total amount of money Sallie earns selling candles
Mathematics
1 answer:
vredina [299]3 years ago
7 0

Answer:

B The number of candles Sallie sells

Step-by-step explanation:

Given the equation :

y = 8x

y = amount earned ; x = number of candles sold

Cost per candle = 8

The Independent variable is the number of candles sallie sells as it is this variable which determines the amount which sallie will earn from candle sales (dependent variable). In essence, the variable which determines or affects the dependent variable is the independent variable.

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A right triangle whose hypotenuse is 3 centimeters long is revolved about one of its legs to generate a right circular cone. Fin
SSSSS [86.1K]

Answer:

The height of the right circular cone when constructed this way is \sqrt3 cm.

The radius of the right circular cone when constructed this way is \sqrt6 cm.

The volume of the right circular cone when constructed this way is 6\sqrt3 \pi cm³.

Step-by-step explanation:

Given that,

A right triangle whose hypotenuse is 3 cm long is revolved .

Then other two legs of the triangle will be radius and height of the cone.

Assume the height and radius of the cone be h and r respectively.

From Pythagorean Theorem :

h²+r²=3²

⇒ r²= 9 - h²

Then the volume of the cone is

V= π r²h

⇒ V= π(9-h²)h                [ ∵ r²= 9 - h²]

⇒V= π(9h - h³)

Differentiating with respect to h

V'=π(9 - 3h²)

Again differentiating with respect to h

V''= π(-6h)

⇒V''= (-6πh)

To maximum or minimum ,we set V'=0

π(9 - 3h²)=0

⇒3h²=9

⇒h²=3

\Rightarrow h=\sqrt3

Now, V''|_{h=\sqrt3}=-6\pi (\sqrt3).

Since at h=\sqrt3,V''<0.

The volume of cone is maximum at h=\sqrt3 cm when constructed this way.

The height of the right circular cone when constructed this way is \sqrt3 cm.

The radius of the right circular cone when constructed this way  r=\sqrt{9-(\sqrt3)^2

   =  \sqrt{9-3}

   =\sqrt6 cm.

The volume of the  right circular cone when constructed this way is

=π r²h

=\pi (\sqrt6)^2\sqrt3

=6\sqrt3 \pi cm³

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