Which is bigger 100 or 10%

Keisha has been given a list of 3 bands and asked to place a vote. Her vote must have the names of her favorite and second favor

BaLLatris [955]

I think the amount of votes you need is 25?

8 0

2 years ago

Ajay reads aloud from a sports magazine. He comes across the measurement 0.63 kilometer. How should he read this measurement alo

Mashutka [201]

Answer:

"sixty-three hundredths of a Kilometer"

Step-by-step explanation:

Decimal measurements are read based on the place of their digits. In this case, Ajay would read this measurement as "sixty-three hundredths of a Kilometer". This is because the final digit of the decimal form measurement is in the "hundredths" position. One more to the right and it would be in the "thousandths" while one more to the left would be the "tenths"

4 0

2 years ago

According to the U.S. Census Bureau, 11% of children in the United States lived with at least one grandparent in 2009 (USA TODAY

wel

Answer:

The pvalue of the test is 0.0001 < 0.02, which means that we reject the null hypothesis and accept the alternate hypohteis that the proportion of all children in the United States who currently live with at least one grandparent is higher than 11%.

Step-by-step explanation:

Proportion of all children in the United States who currently live with at least one grandparent is higher than 11%

This means that the null hypothesis is:

$H_0: p = 0.11$

And the alternate hypothesis is:

$H_a: p > 0.11$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.11 is tested at the null hypothesis:

This means that $\mu = 0.11, \sigma = \sqrt{0.11*0.89}$

Suppose that in a recent sample of 1550 children, 214 were found to be living with at least one grandparent.

This means that:

$n = 1550, X = \frac{214}{1550} = 0.1381$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.1381 - 0.11}{\frac{\sqrt{0.11*0.89}}{\sqrt{1550}}}$

$z = 3.54$

Pvalue of the test and decision:

This is the probability of finding a sample proportion above 0.1381, which is 1 subtracted by the pvalue of Z = 3.54.

$z = 3.54$ has a pvalue of 0.9999

1 - 0.9999 = 0.0001

The pvalue of the test is 0.0001 < 0.02, which means that we reject the null hypothesis and accept the alternate hypohteis that the proportion of all children in the United States who currently live with at least one grandparent is higher than 11%.

8 0

2 years ago

Maya’s paycheck shows that her gross pay was $497.32. Her payroll taxes totaled $83.12. How much was Maya’s net income for this

NISA [10]

Answer:

$497.32 - $83.12 =$414.20

Step-by-step explanation:

4 0

3 years ago

Solve this linear equation by graphing <br> 1/2x-y=4<br> 2y=x+6

Oliga [24]

Answer:

see attachment for answer.

Step-by-step explanation:

1/2x-y=4 and 2y=x+6 plot

5 0

2 years ago