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Gre4nikov [31]
3 years ago
10

I got it partially right I think but I need help !

Mathematics
1 answer:
Papessa [141]3 years ago
6 0

Answer:

U got it correct

Step-by-step explanation:

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Rick bikes 24 miles in 3/4 of an hour.what is his speed in miles per hour.
jenyasd209 [6]

Answer:

32 MPH

Step-by-step explanation:

MPH= Distance/Time

24/(3/4)= 24*4/3 = 96/3 = 32 MPH

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How would I do this problem? In trapezoid PQRS, PQ is parallel to SR. Find the area of PQRS. Leave your answer is simplest radic
Mrac [35]
Can u take its pictures and post it bcuz it might be easer to answer
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Find the area of the shaded region
snow_tiger [21]

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42.92

Step-by-step explanation:

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What is the surface area of this composite figure?
faust18 [17]

Answer:

<h2>          294 cm²</h2>

Step-by-step explanation:

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4 0
3 years ago
) Evaluating a polynomial limit analytically You should have learned by now the process for finding the derivative of a polynomi
wolverine [178]

Answer:

This code or is program to find a given value of derivative of  a polynomial.

Step-by-step explanation:

We know already how to apply or make the procedures mathematically talking so this short program will eventually help you how to find logic.

// libraries

#include <stdio.h>

#include <conio.h>

//use to control floating elements

float poly(float a[], int, float);

//main

int main()

{

// Enter the degree of polynomial equation

float x, a[10], y1;

int deg, i;

printf("Enter the degree of polynomial equation: ");

scanf("%d", &deg);

printf("Ehter the value of x for which the equation is to be evaluated: ");

// Enter the coefficient of x to the power

scanf("%f", &x);

for(i=0; i<=deg; i++)

{

 printf("Enter the coefficient of x to the power %d: ",i);

 scanf("%f",&a[i]);

}

// The value of polynomial equation for the value of x

y1 = poly(a, deg, x);

 

printf("The value of polynomial equation for the value of x = %.2f is: %.2f",x,y1);

 

return 0;

}

/* function for finding the value of polynomial at some value of x */

float poly(float a[], int deg, float x)

{

float p;

int i;

 

p = a[deg];

 

for(i=deg;i>=1;i--)

{

 p = (a[i-1] + x*p);

}

 

return p;

}

8 0
3 years ago
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