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3 years ago

12

Let u = <9,4>, v = <-2,5>. Find u + v.

2 answers:

Alekssandra [29.7K]3 years ago

7 0

Answer:

c) (7, 9)

Step-by-step explanation:

Simply add the corresponding coordinates.

Mekhanik [1.2K]3 years ago

6 0

Answer:

Download PHOTO MATH trust me you will pass math. :) hope this helped

Step-by-step explanation:

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3 years ago

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Answer the 3 screenshotted questions below. 30 points!

Triss [41]

Answer:

13. $36a^2b^4$ π

14. $16x^3y^4$ π

15. $-\frac{c^3}{4a^7b^3}$

Step-by-step explanation:

13.

A = π * $r^2$

r = $6ab^2$

A = π* $(6ab^2)^2$

A = π * $(6ab^2)(6ab^2)$

A = π * $36a^2b^4$

A = $36a^2b^4$ π

14.

V = π * $r^2$ * h

r = $2x$

h = $4xy^4$

V = π * $(2x)^2$ * $4xy^4$

V = π * $4x^2$ * $4xy^4$

V = π * $16x^3y^4$

V = $16x^3y^4$ π

15. $\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$ = $-\frac{c^3}{4a^7b^3}$

$\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$

$\frac{a^{-4}}{-4a^3b^5c^{-3}}$

$\frac{b^2}{-4^{3+4}b^5c^{-3}}$

$\frac{b^2}{-4^7b^5c^{-3}}$

$\frac{1}{-4a^7b^{5-2}c^{-3}}$

$\frac{1}{-4a^7b^3c^{-3}}$

$\frac{c^3}{-4a^7b^3}$

$-\frac{c^3}{4a^7b^3}$

Hope this helps!

3 0

3 years ago

Help asap I will give u huge amount of brainly points

Minchanka [31]

Answer:

$\boxed{\sf -\dfrac{5}{8}}$

Use BODMAS rule,

where:

brackets
order
division
multiplication
addition
subtraction

Given expression:

$\rightarrow \sf -\dfrac{1}{5} \times [\:4-14\times\left(\dfrac{1}{4} \right)^2]$

simplify exponent

$\rightarrow \sf -\dfrac{1}{5} \times [\:4-14\times\left(\dfrac{1}{16} \right)]$

$\rightarrow \sf -\dfrac{1}{5} \times [\:4-\(\dfrac{14}{16}]$

$\rightarrow \sf -\dfrac{1}{5} \times [\:4-\(\dfrac{7}{8}]$

$\rightarrow \sf -\dfrac{1}{5} \times [\:\dfrac{32}{8} -\(\dfrac{7}{8}]$

$\rightarrow \sf -\dfrac{1}{5} \times [\:\dfrac{25}{8}]$

multiply fractions

$\rightarrow \sf -\dfrac{25}{40}$

$\rightarrow \sf -\dfrac{5}{8}$

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