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3 years ago

5

What information is shown in the infographics?

1 answer:

daser333 [38]3 years ago

3 0

Answer:

An infographic is a collection of imagery, charts, and minimal text that gives an easy-to-understand overview of a topic. As in the example below, infographics use striking, engaging visuals to communicate information quickly and clearly. Infographics are a valuable tool for visual communication.

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Which method is suitable for collection a a<br>carbon dioxide.Explain

mel-nik [20]

Answer:

Carbon dioxide can be collected over water. Carbon dioxide is slightly soluble in water and denser than air, so another way to collect it is in a dry, upright gas jar.

Explanation:

8 0

3 years ago

Whats the molar mass of tetraphosphorus decoxide

Savatey [412]

<span>283.89 g/mol is the molar mass of tetraphosphorus decoxide</span>

4 0

4 years ago

Below is a word equation. Please follow directions for each part below.

Pavel [41]

HCl + NaOH ---> NaCl + H20

If you follow guidance from other questions I have already answered for you, you will see that the above equation is balanced as it is.

4 0

3 years ago

Which of these is a problem with using nuclear energy?

Nadusha1986 [10]

Answer:

D

We don't have a way to contain the radioactive waste produced.

Explanation

Nuclear waste is non disposable and takes millions of years to biodegrade and lose it radio activeness

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4 years ago

In part 2 of the experiment, you will be analyzing a sample of household bleach. A 0.0854 g sample of household bleach is comple

marysya [2.9K]

Answer:

The correct answer is option d.

Explanation:

$NaClO(aq)+2KI(s)+H_2O(l)\rightarrow NaCl(aq)+I_2(aq)+2KOH(aq)$ ..[1]

$I_2(aq)+2Na_2S_2O_3(aq)\rightarrow 2NaI(aq)+Na_2S_4O_6(aq)$ ..[2]

moles of sodium thiosulfate solution = n

Molarity of the sodium thiosulfate solution = 0.150 M

Volume of sodium thiosulfate solution used = 0.890 mL = 0.00089 L

$n=Molarity\times Volume (L)$

$n=0.150 M\times 0.00089 L=0.0001335 mol$

According to reaction [2], 2 moles of sodium thiosulfate reacts with 1 mol $I_2$ .

Then , 0.0001335 mol of sodium thiosulfate will reacts with:

$\frac{1}{2}\times 0.0001335 mol=0.00006675 mol$ of $I_2$

Moles of $I_2$ = 0.00006675 mol

According to reaction [1], 1 mol of $I_2$ is obatnied from 1 mol of NaClO.

Then 0.00006675 mol of $I_2$ will be obtained from:

$\frac{1}{1}\times 0.00006675 mol=0.00006675 mol$

Mass of 0.00006675 mol of NaClO=

0.00006675 mol × 74.44 g/mol = 0.00496887 g

Mass of sample = 0.0854 g

Percentage of NaClO in sample:

$\frac{0.00496887 g}{0.0854 g}\times 100=5.82\%$

4 0

4 years ago