C(HClO) = 0,3 M.
<span>V(HClO) = 200 mL = 0,2 L.
n(HClO) = </span>c(HClO) · V(HClO).
n(HClO) = 0,06 mol.<span>
c(KClO</span>) =
0,2 M.
<span>V(KClO) = 0,3 L.
n(KClO) = 0,06 mol.
V(buffer solution) = 0,2 L + 0,3 L = 0,5 L.
ck</span>(HClO) = 0,06 mol ÷ 0,5 L = 0,12 M.
cs(KClO) = 0,06 mol ÷ 0,5 L = 0,12 M.<span>
Ka(HClO</span>) =
2,9·10⁻⁸.<span>
This is buffer solution, so use Henderson–Hasselbalch
equation:
pH = pKa + log(cs</span> ÷ ck).<span>
pH = -log(</span>2,9·10⁻⁸) + log(0,12 M ÷ 0,12 M).<span>
pH = 7,54 + 0.
pH = 7,54</span>
C₂H₆O is referred to the chemical formula corresponds to this structural formula and is denoted as option D.
<h3>What is Chemical formula?</h3>
This contains information about the chemical proportion of atoms present in a molecule.
In this scenario, there are two carbon atoms, six hydrogen atoms and one oxygen atom which can be written as C₂H₆O. This is therefore the most appropriate choice in this scenario.
Read more about Chemical formula here brainly.com/question/26388921
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Answer: The mass of given amount of copper (II) cyanide is 462.4 g
Explanation:
To calculate the number of moles, we use the equation:
We are given:
Moles of copper (II) cyanide = 4 moles
Molar mass of copper (II) cyanide = 115.6 g/mol
Putting values in above equation, we get:
Hence, the mass of given amount of copper (II) cyanide is 462.4 g
Volume is the thing
…………….
Answer:
When you put sugar inside of a cup with water, the sugar is still visible because it's molecules have just gotten in touch with water molecules. The sugar molecules are still attracted to each other but as you stir it, it seems to disappear but not completely. When the water is stirred sugar mix with water and water molecules place themselves between the sugar ones.
Conclusion: It suggests that the sugar molecules are more attracted to water molecules which is why they easily separate from each other.
