Question

How many 20.0-g ice cubes are required to absorb 47.0 kJ from a glass of water upon melting?

Answer 1

Hello!

The number of 20-g ice cubes required to absorb 47 kJ from a glass of water upon melting is 7 icecubes

Why?

We are going to clear from the equation of the released heat, the mass of ice (m). The specific latent heat of fusion of ice is 336 kJ/kg:

$Q=m*L\\ \\ m=\frac{Q}{L}=\frac{47 kJ}{336 kJ/kg}=0,1399 kg=139,88 g\\ \\ 139,88g*\frac{1 icecube}{20g}=6,99=7icecubes$

So, 7 ice cubes are required to absorb that amount of heat from the glass of water.

Have a nice day!