The mass percentage composition of nitrogen in CO(NH2)2 is 46 .7%
calculation
% mass = molar mass of nitrogen/ molar mass of Co(NH2)2
molar mass of nitrogen = 14 x2 = 28g/mol since there is two nitrogen atom in Co(NH2)2\
molar mass of CO(NH2)2 = 12 + 16 + (14 x2) +( 2 x2)= 60 g/mol
the % mass is therefore =28 / 60 x100 =46.7%
Answer:
3,717,813
Im not sure, I will get back to you soon
Um I don’t know what stoichiometry is. So I can’t help I am sorry wish I could