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3 years ago

Prove:(coseca-sina)(seca-cosa)(tana+cota)=1

Mathematics

1 answer:

jolli1 [7]3 years ago

8 0

Anis that cosine and sine?

Step-by-step explanation:

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8 and 1/5 + 4 and 2/5=?

Leviafan [203]

12 and 3/5 hope this helped

4 0

3 years ago

Use the substitution method to solve the system of equations. Choose the correct ordered pair.

motikmotik

Ur gonna have to pick an equation and solve for a variable.

2x - 2y = 6
2x = 2y + 6 ...divide everything by 2 because u want x by itself
x = y + 3

now we sub y + 3 in for x in the other equation
14x - 2y = 78
14(y + 3) - 2y = 78...distribute thru the parenthesis
14y + 42 - 2y = 78...subtract 42 from both sides, cancelling the 42 on the left
-42 -42
-----------------------
14y - 2y = 36 ...simplify
12y = 36...divide by 12 on both sides, cancelling out the 12 on the left
y = 36/12
y = 3

now , we already know that x = y + 3...and we know y = 3...so sub in 3 for y and solve for x
x = y + 3
x = 3 + 3
x = 6

solution is (6,3)

it is always a good idea to check ur answer by subbing it into one or both of the equations to see if it is correct
2x - 2y = 6......(6,3)...x = 6 and y = 3
2(6) - 2(3) = 6
12 - 6 = 6
6 = 6 (correct)

so yes, ur solution is (6,3)

4 0

2 years ago

Read 2 more answers

PLease help asap

liubo4ka [24]

Nvm disregard or delete this... wrong answer

8 0

2 years ago

Read 2 more answers

During a weekend the manager of a mall gave away gift cards to every 80th person who visited the mall. On saturday 12010 on sund

inysia [295]

Answer:

172.8 people got a gift card

Step-by-step explanation:

12,010 + 1,814 = 13,824 divided 80

= 172.8 people got a gift card

6 0

3 years ago

F(x) = 2x^2 − 3x − 5 Part

riadik2000 [5.3K]

Answer: Answer is in the steps..

Step-by-step explanation:

f(x)= $2x^{2}$ - 3x -5

A) To find the x intercepts of a parabola we have to set the whole equation equal zero because the x intercept is when y equal zero in other words where f(x) equal zero.

$2x^{2}$ - 3x - 5 = 0 Now solve using quadratic formula.

x = -b± $\frac{\sqrt{b^2 -4ac } }{2a}$

x = 3 ± $\sqrt{9+40} /2a$

x = 3 ± $\sqrt{49}$ / 2a

x= 3 ± 7 /4

x= -1 or x = 5/2

The x intercepts are (5/2,0) and (-1,0)

B) The graph vertex of the graph of f(x) is going to be at a minimum because the leading coefficient of the function has a positive integer which means the parabola will open up and its vertex will be at the minimum point.

Using the x coordinates we could find their average and find the x coordinate of the vertex.

$\frac{5}{2} + -\frac{1}{1}$ = $\frac{3}{2} / \frac{2}{1}$ = 3/4

The x coordinate of the vertex is 3/4 so we will input that into the equation and solve for the y coordinate

$2(\frac{3}{4})^2 - 3 (\frac{3}{4}) - 5$ = 18/16 - 9/4 -5 = -49/8

The y coordinate of the vertex is -49/8

So the vertex is (3/4, -49/8)

C) First I will graph the vertex and then graph he two x intercepts and connect then like a U shape.

5 0

3 years ago