Question

I need help with these questions :(see image )​

Answer 1

Hey There!

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Answer:

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DATA:

Height of Aeroplane = 500 meters

Speed of Aeroplane = 200 m/s

Acceleration due to gravity = g = 10m/s^2

time of package to reach the ground = t = ?

Horizontal distance = d = ?

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SOLUTION:

When the bomb is dropped, it will have an initial horizontal velocity which is equal to the speed of the plane as the plane is just moving in horizontal direction. So the bomb fall and will travel forward.

Initial horizontal velocity is given by,

                                            $V_{ix} = 200 ms{-1}$

Initial vertical velocity is given by,

                                            $V_{iy} = 0m/s$

By the second equation of motion under gravity,

                                           $H = V_{iy}t + \frac{1}{2}gt^2\\\\500 = (0)t + \frac{1}{2}x10xt^2 \\\\500 = 0 + 5t^2\\\\t^2 = \frac{500}{5}\\\\t^2 = 100\\\\t = 10 seconds$

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For horizontal distance(d):

Horizontal distance has no acceleration thus d is given by

                                          d = vt

                                          d = 200x10

                                          d = 2000 meters

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Best Regards,

'Borz'