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3 years ago

You kick a ball with a speed of 14 m/s at an angle of 51 degrees. How far away does the ball land?

Physics

2 answers:

Triss [41]3 years ago

8 0

<u>Answer:</u> The ball will land at 19.6 m

<u>Explanation:</u>

To calculate the horizontal range of the ball, we use the formula:

$R=\frac{v^2\sin 2\theta}{g}$

where,

v = velocity of the ball = 14 m/s

$\theta$ = angle at which the ball is thrown = 51°

g = acceleration due to gravity = $9.8m/s^2$

Putting values in above equation, we get:

$R=\frac{(14)^2\times \sin (2\times 51)}{9.8}\\\\R=19.6m$

Hence, the ball will land at 19.6 m

zvonat [6]3 years ago

5 0

D may be the correct answer because speed is very low so ball should cover less distance but angle is not very high so it can cover little much distance

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One end of a 34-m unstretchable rope is tied to a tree; the other end is tied to a car stuck in the mud. The motorist pulls side

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Answer:

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