Question

You kick a ball with a speed of 14 m/s at an angle of 51 degrees. How far away does the ball land?

Answer 1

Answer: The ball will land at 19.6 m

Explanation:

To calculate the horizontal range of the ball, we use the formula:

$R=\frac{v^2\sin 2\theta}{g}$

where,

v = velocity of the ball = 14 m/s

$\theta$ = angle at which the ball is thrown = 51°

g = acceleration due to gravity = $9.8m/s^2$

Putting values in above equation, we get:

$R=\frac{(14)^2\times \sin (2\times 51)}{9.8}\\\\R=19.6m$

Hence, the ball will land at 19.6 m

Answer 2

D may be the correct answer because speed is very low so ball should cover less distance  but angle is not very high so it can cover little much distance