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r-ruslan [8.4K]
3 years ago
10

You kick a ball with a speed of 14 m/s at an angle of 51 degrees. How far away does the ball land?

Physics
2 answers:
Triss [41]3 years ago
8 0

<u>Answer:</u> The ball will land at 19.6 m

<u>Explanation:</u>

To calculate the horizontal range of the ball, we use the formula:

R=\frac{v^2\sin 2\theta}{g}

where,

v = velocity of the ball = 14 m/s

\theta = angle at which the ball is thrown = 51°

g = acceleration due to gravity = 9.8m/s^2

Putting values in above equation, we get:

R=\frac{(14)^2\times \sin (2\times 51)}{9.8}\\\\R=19.6m

Hence, the ball will land at 19.6 m

zvonat [6]3 years ago
5 0
D may be the correct answer because speed is very low so ball should cover less distance  but angle is not very high so it can cover little much distance
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