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LiRa [457]
3 years ago
14

Are the following even, odd, or neither f(x)=5x^3-2x

Mathematics
1 answer:
kaheart [24]3 years ago
6 0

Answer:

positive

Step-by-step explanation:

if x is positive then for all values 5x^3 which is always>-2x will be positive and therefore answer always positive

if x is negative then  5x^3 will always be positive and  -2(X)  will cancel the two minuses -- and will add therefore positive

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Find the product. Simplify. 1/10 x 3/4
FrozenT [24]

Answer:

Alright just simplify the expression So the exact form is

Exact form: 3/40 Hope this helps :)

Step-by-step explanation:


6 0
3 years ago
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PLZ ANSWER THIS<br> thanksssss
just olya [345]

Answer:

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Step-by-step explanation:

5 0
2 years ago
The equation 9 x 2 − 12 x + 4 = 0 9 x 2 − 12 x + 4 = 0 has how many different solutions?
Hatshy [7]

We have the equation:

9x^2-12x+4=0

so:

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2 years ago
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Ivahew [28]
The area of your game board is = 126 * 90 = 11340 cm^2;
A small suares has x^2 his area; where x measure his length;

Prime factorization

11340 | 2
 5670 | 2
 2835 | 5
  567  | 3
  189 | 3
    63 | 3
    21 | 3
      7 | 7
      1

11340 = 2^2 * 3^4 * 5 * 7 = 2^2 * ( 3^2 ) ^ 2 * 5 * 7 = 18^2 * 5 * 7

We observ that the possible length of the side is 18( we have 35 small squares ).
8 0
3 years ago
The function f(x)=2^x and g(x)=f(x+k). If k=-5,what can be concluded about the graph of g(x)?
melamori03 [73]
\bf ~~~~~~~~~~~~\textit{function transformations}&#10;\\\\\\&#10;% templates&#10;f(x)=  A(  Bx+  C)+  D&#10;\\\\&#10;~~~~y=  A(  Bx+  C)+  D&#10;\\\\&#10;f(x)=  A\sqrt{  Bx+  C}+  D&#10;\\\\&#10;f(x)=  A(\mathbb{R})^{  Bx+  C}+  D&#10;\\\\&#10;f(x)=  A sin\left( B x+  C  \right)+  D&#10;\\\\&#10;--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\&#10;\bullet \textit{ flips it upside-down if }  A\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }  B\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the y-axis}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{  C}{  B}\\&#10;~~~~~~if\ \frac{  C}{  B}\textit{ is negative, to the right}

\bf ~~~~~~if\ \frac{  C}{  B}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }  D\\&#10;~~~~~~if\   D\textit{ is negative, downwards}\\\\&#10;~~~~~~if\   D\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{  B}

with that template in mind

\bf f(x)=2^x\qquad &#10;\begin{cases}&#10;g(x)=f(x+k)&k=5\\&#10;\qquad\quad f(x+5)\\&#10;\qquad \quad 2^{x+5}&#10;\end{cases}

notice, in g(x)

B = 1, no change from parent

C= +2



8 0
3 years ago
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