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Mariulka [41]
2 years ago
15

Arithmetic sequence of -10,8,26

Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
5 0

Answer:

the sequence is going up by 18

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Find the value of x .. assume that segments that appear to be tangent are tangent .
Rus_ich [418]

Answer:

sqrt(277) =x

x is approximately 16.64331698

Step-by-step explanation:

This is a right triangle since 14 is tangent to the circle and 9 is a radius

We can use the Pythagorean theorem to solve this problem

a^2 +b^2 =c^2

9^2+14^2 =x^2

81+196 = x^2

277 = x^2

Taking the square root of each side

sqrt(277) = sqrt(x^2)

sqrt(277) =x

6 0
2 years ago
A factory inspector found flaws in 3 out of 18 wooden boxes what is the experimental probability that the next wooden box will b
Sphinxa [80]

Answer:

16.666% would be flawed.

Step-by-step explanation:

7 0
2 years ago
A parallelogram has symmetry with respect to the point of intersection of its diagonals. t/f?
Anna007 [38]
It is true that a parallelogram has symmetry with respect to the point of intersection of its diagonals. 
5 0
3 years ago
Find two consecutive even integers such that the smaller added to three times the larger gives a sum of 54
REY [17]
Let n be the first even integer, and n+2 will be the second even integer. (Why? Think 2 and 4, 2+2=4. This is the case for every consecutive even integers).

n + 3(n+2) = 54
n + 3n + 6 = 54
4n = 48
n = 12, n+2 = 14
7 0
3 years ago
Read 2 more answers
. A right cylindrical drum is to hold 7.35 cubic feet of liquid. Find the dimensions (radius of the base and height) of the drum
Drupady [299]

Answer:

r=1.05\ \text{ft}

h=2.12\ \text{ft}

20.91\ \text{ft}^3

Step-by-step explanation:

r = Radius

h = Height

Volume of cylinder = 7.35\ \text{ft}^3

V=\pi r^2h\\\Rightarrow h=\dfrac{V}{\pi r^2}\\\Rightarrow h=\dfrac{7.35}{\pi r^2}

Surface area is given by

A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi r^2+2\pi r\dfrac{7.35}{\pi r^2}\\\Rightarrow A=2\pi r^2+\dfrac{14.7}{r}

Differentiating with respect to radius we get

\dfrac{dA}{dr}=4\pi r-\dfrac{14.7}{r^2}

Equating with zero we get

0=4\pi r-\dfrac{14.7}{r^2}\\\Rightarrow 4\pi r=\dfrac{14.7}{r^2}\\\Rightarrow r^3=\dfrac{14.7}{4\pi}\\\Rightarrow r=(\dfrac{14.7}{4\pi})^{\dfrac{1}{3}}\\\Rightarrow r=1.05

\dfrac{d^2A}{dr^2}=4\pi-2\times \dfrac{14.7}{r^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=4\pi+2\times \dfrac{14.7}{1.05^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=37.96>0

So, the value of the function is minimum at r=1.05

h=\dfrac{7.35}{\pi r^2}=\dfrac{7.35}{\pi 1.05^2}\\\Rightarrow h=2.12

So, the radius and height which would minimize the surface area is 1.05 feet and 2.12 feet respectively.

Surface area

A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi \times 1.05^2+2\pi 1.05\times 2.12\\\Rightarrow A=20.91\ \text{ft}^3

The minimum surface area is 20.91\ \text{ft}^3.

8 0
3 years ago
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