We must find UNIQUE combinations because choosing a,b,c,d... is the same as d,c,b,a...etc. For this type of problem you use the "n choose k" formula...
n!/(k!(n-k)!), n=total number of choices available, k=number of choices made..
In this case:
20!/(10!(20-10)!)
20!/(10!*10!)
184756
Answer:
m=22.2
Step-by-step explanation:
By using the Pythagorean’s theorem i.e
hypotenuse^2=opposite^2+adjacent^2
Where
Hypotenuse =unknown
Opposite =18
Adjacent =13
Hyp^2=18^2+13^2
Hyp^2=324+169
Hyp^2=493
Hyp=sqrt 493
Hyp=m=22.2
Answer:hello :
tanA = sinA/cosA
cosA = sinA /tanA
cosA =(4/5)/(4/3)
cosA=3/5
Step-by-step explanation:
3-y/2=1
-3 -3
-y/2=-2
x2 x2
-y=-4
/-1 /-1
Y=4
