Answer: you are correct the correct answer is A
Answer:
- <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>
Explanation:
<u>Rewrite the table and the choices for better understanding:</u>
<em>Enrollment at a Technical School </em>
Year (x) First Year f(x) Second Year s(x)
2009 785 756
2010 740 785
2011 690 710
2012 732 732
2013 781 755
Which of the following statements is true based on the data in the table?
- The solution to f(x) = s(x) is x = 2012.
- The solution to f(x) = s(x) is x = 732.
- The solution to f(x) = s(x) is x = 2011.
- The solution to f(x) = s(x) is x = 710.
<h2>Solution</h2>
The question requires to find which of the options represents the solution to f(x) = s(x).
That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.
The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>
Thus, the correct choice is the third one:
- The solution to f(x) = s(x) is x = 2012.
Answer:
Exterior angle = sum of opposite interior angles
Step-by-step explanation:
68 minus 19 is 49
So the answer is there are 49 more children in the school then on the playground.
Answer:
b. 58%
Step-by-step explanation:
Calculate the area of the entire rectangle using the formula A = lw.
The lowercase "L" is for length.
"w" is for width.
The lighter square is 10 units long by 5 inches wide.
A = lw
A = (10 in)(5 in) Multiply
A = 50 in²
Calculate the area for the shaded rectangle, 7 inches by 3 inches.
A = lw
A = (7 in)(3 in) Multiply
A = 21 in²
Calculate the area for the non-shaded region by subtracting the shaded area from the total area.
50 in² - 21 in² = 29 in²
The chance that a point in the large rectangle will NOT be in the shaded region is 29/50.
Convert this fraction to decimal form by using a calculator. Divide the top number by the bottom number.
29/50 = 0.58
0.58 is in decimal form. To convert it to a percentage, multiply the number by 100.
0.58 = 58%
Therefore the probability that a point chosen inside the large rectangle is not in the shaded region is 58%.
