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Troyanec [42]
3 years ago
8

A rectangle has an area of 364.5 cm2. If its length is 27 cm, find its perimeter.

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0
Wiskksjkxkc jefe jifvnjcrg morboso
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A programmer wants to display how the shape of a rectangle with a fixed perimeter of 300 inches can be changed by varying the re
stiv31 [10]

If the rectangle has a fixed width of 300, it means that

2(l+w)=300 \iff l+w=150 \iff w=150-l

where w and l are width and length, respetively.

So given the length l, the are would be

l\times w = l\times (150-l)=-l^2+150l

7 0
3 years ago
What is the unit form using the largest unit possible for 4tens+6tens
Gre4nikov [31]
40 + 60 = 100

Hundrends place
4 0
3 years ago
A bookstore bought a case of 10 books for a wholesale price of $74. The bookstore will sell the books at a 20% markup. How much
Darya [45]

Answer:

8.88 dollars so D

Step-by-step explanation:

3 0
3 years ago
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What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
xxMikexx [17]

We have been given an equation of hyperbola \frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1. We are asked to find the center of hyperbola.  

We know that standard equation of a vertical hyperbola is in form \frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1, where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1

Now we can see that value of k is -3. Therefore, the vertex of given hyperbola will be at point (6,-3) and option D is the correct choice.

6 0
3 years ago
Isaac walks 6/10 of a mile in 1/5 of an hour. If Isaac’s walking rate remains constant, what is Isaac’s walking rate in miles pe
navik [9.2K]

Answer:

12

Step-by-step explanation:

u have to mutypl and div it up sum and k/=+56+8=90/h=+5689-097/p=11+y=1+11=12

4 0
3 years ago
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