Question

Help!!!!!!!!!!!!!!!!!!

Answer 1

The density of the sample : 0.827 g/L

Further explanation

In general, the gas equation can be written  

$\large {\boxed {\bold {PV = nRT}}}$

where  

P = pressure, atm , N/m²

V = volume, liter  

n = number of moles  

R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m2, v= m³)

T = temperature, Kelvin  

n= 1 mol

MW Neon = 20,1797 g/mol

mass of Neon :

$\tt mass=mol\times MW\\\\mass=1\times 20,1797 =20.1797~g$

The density of the sample :

$\tt \rho=\dfrac{m}{V}\\\\\rho=\dfrac{20,1797}{24.4}=0.827~g/L$

or We can use the ideal gas formula ta find density :

$\tt \rho=\dfrac{P\times MW}{RT}\\\\\rho=\dfrac{1\times 20.1797}{0.082\times 298}\\\\\rho=0.826~g/L$