I need more information, there are meant to be coefficients in front of one of those ..
but you’d put .2 over the coefficients, and if there is not one, you put an X. then you will cross multiply, and divide if you have 2x or something greater than X.
I need points sorry I’m doing a test
Answer:
freezing point (°C) of the solution = - 3.34° C
Explanation:
From the given information:
The freezing point (°C) of a solution can be prepared by using the formula:

where;
i = vant Hoff factor
the vant Hoff factor is the totality of the number of ions in the solution
Since there are 1 calcium ion and 2 nitrate ions present in Ca(NO3)2, the vant Hoff factor = 3
= 1.86 °C/m
m = molality of the solution and it can be determined by using the formula

which can now be re-written as :



molality = 0.599 m
∴
The freezing point (°C) of a solution can be prepared by using the formula:



the freezing point of water - freezing point of the solution
3.34° C = 0° C - freezing point of the solution
freezing point (°C) of the solution = 0° C - 3.34° C
freezing point (°C) of the solution = - 3.34° C
That would be Iodine Heptafluoride.
Hope this helps!