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3 years ago

How to solve a quadratic equation by making a perfect square?

1 answer:

3 0

1. Rewrite the equation in the form x2 +bx<span> = </span>c.
2. Add to both sides the term needed to complete the square.
3. Factor the perfect square trinomial.
<span>4. Solve the resulting equation by using the square root property.</span>

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***PLEASE HELP WILL GIVE BRAINLIEST!!!***

Ede4ka [16]

in the number line, the end points are DG, and the point in between is O

DG = 88

DO = 5x + 12

OG = 2x

Set the equation. The two parts (DO & OG) are equal to the whole (DG)

2x + 5x + 12 = 88

Simplify. Combine like terms

(2x + 5x) + 12 = 88

7x + 12 = 88

Isolate the x. Remember to do the opposite of PEMDAS. Subtract 12 from both sides

7x + 12 (-12) = 88 (-12)

7x = 76

Isolate the x. Divide 7 from both sides:

7x/7 = 76/7

x = 76/7

----------------------------------------------------------------------------------------------------------------------------

Find DO. Plug in "76/7" for x:

DO = 5x + 12

DO = 5(76/7) + 12

Simplify. Remember to follow PEMDAS. Multiply 76 with 5

DO = 380/7 + 12

Next, divide 380 with 7

DO = 54.29 (rounded)

Finally, add

DO = 54.29 + 12

DO = 66.29

66.29 is your answer

hope this helps

4 0

4 years ago

Each of the 25 students in Mr Walker's class sold 16 raffle tickets. If each ticket costs $15 how much money did Mr Walker's stu

ludmilkaskok [199]

Answer: $6000

Hope this helps!-xoxo

5 0

4 years ago

Solve the following equation for y.

vfiekz [6]

Answer:

Y=2x-13 ...................

6 0

3 years ago

Read 2 more answers

26-4=12+ missing number

saw5 [17]

22-12=10

so this missing answer after the + is 10

7 0

3 years ago

Read 2 more answers

For which function is f(x) equal to f^1(x) ( answer choices in picture )

Sonja [21]

Answer:

C. $f(x)=\frac{x+1}{x-1}$

Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

$f(x)=\frac{x+6}{x-6}\\y=\frac{x+6}{x-6}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+6}{y-6}$

Rewrite in terms of 'y'. This gives,

$x(y-6)=y+6\\xy-6x=y+6\\xy-y=6x+6\\y=\frac{6x+6}{x-1}$

The given function $y=\frac{6x+6}{x-1}\ne y=\frac{x+6}{x-6}$

So, option A is incorrect.

Option B:

$f(x)=\frac{x+2}{x-2}\\y=\frac{x+2}{x-2}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+2}{y-2}$

Rewrite in terms of 'y'. This gives,

$x(y-2)=y+2\\xy-2x=y+2\\xy-y=2x+2\\y=\frac{2x+2}{x-1}$

The given function $y=\frac{2x+2}{x-1}\ne y=\frac{x+2}{x-2}$

So, option B is incorrect.

Option C:

$f(x)=\frac{x+1}{x-1}\\y=\frac{x+1}{x-1}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+1}{y-1}$

Rewrite in terms of 'y'. This gives,

$x(y-1)=y+1\\xy-x=y+1\\xy-y=x+1\\y=\frac{x+1}{x-1}$

The given function $y=\frac{x+1}{x-1}\ equals\ y=\frac{x+1}{x-1}$

So, option C is correct.

Option D:

$f(x)=\frac{x+5}{x-5}\\y=\frac{x+5}{x-5}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+5}{y-5}$

Rewrite in terms of 'y'. This gives,

$x(y-5)=y+5\\xy-5x=y+5\\xy-y=5x+5\\y=\frac{5x+5}{x-1}$

The given function $y=\frac{5x+5}{x-1}\ne y=\frac{x+6}{x-6}$

So, option D is incorrect.

Therefore, only option C is correct.

7 0

3 years ago