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3 years ago

PLEASE HELP (LOOK AT THE PICTURE) Write an equation for the given graph.

Mathematics

1 answer:

tino4ka555 [31]3 years ago

3 0

The answer should be C. y=-3x+7

use the formula y=mx+b where mx is the slope and b is the y-intercept.

in this case, the slope is decreasing by 3 so -3 would fit in for mx. if you look on the y-int you’ll see that the value is positive 7.

when you put this together, you’d get the equation y=-3x+7

hope this helps.

You might be interested in

100m world record was completed at an average speed of 37.6 km/h. work out this speed in meters per second?

pickupchik [31]

Step-by-step explanation:

1 km = 1000 m

1 hour = 3600 s

so,

37.6 km = 37,600 m (still per hour or per 3600 s).

in 1 second now that is

37600/3600 = 10.44444444... m/s

4 0

1 year ago

Brady rode his bike 70 miles in 4 hours. He rode at an average speed of 17 miles per hour for t hours and at an average rate of

IceJOKER [234]

Answer:

Brady rides at slower speed which is 17 miles/hours for <em><u>3 hours and 36 minutes.</u></em>

Step-by-step explanation:

Given:

Brady rode 70 miles in 4 hours.

For $t$ hours he rode at the average rate of 17 miles/hour

For rest of the time he rode at the average rate of 22 miles per hour.

To find the time Braady rode at the slower speed.

Solution:

Total time of riding = 4 hours

Time for which Brady rides at 17 miles/ hour = $t$ hours

Distance covered in $t$ hours = $Speed\times time=17\times t =17t\ miles$

So, time for which Brady rides at 22 miles/ hour = $(4-t)$ hours

Distance covered in $(4-t)$ hours = $Speed\times time=22\times(4-t) =(88-22t)\ miles$

Total distance can be given as:

⇒ $17t+88-22t$

Simplifying.

⇒ $-5t+88$

Total distance given =70 miles.

Thus, the equation to find $t$ can be given as:

$-5t+88=70$

Subtracting both sides by 88.

$-5t+88-88=70-88$

$-5t=-18$

Dividing both sides by -5.

$\frac{-5t}{-5}=\frac{-18}{-5}$

∴ $t=3.6$ hours

$3.6\ hours = 3\ hour+ (0.6\times 60)\ minutes = 3\ hour\ 36\ minutes$

Thus, Brady rides at slower speed which is 17 miles/hours for 3 hours and 36 minutes.

6 0

2 years ago

I need help with these two

Dmitrij [34]

19.

A) 84 : 120 --) 7 : 10, I came up with it by knowing x, # of times ordered,

7(x) : 3(x) sum will be 120 and guessed from there.

B) Well I came up with it trying to get the ratio for A, 84 smoothies.

C) 84 ( smoothies) - 36 ( juice drinks)

20.

A) Ok you first have the birds from the first hour which sum up to 24. Then to calculate what of how many birds you saw for the second hour you use the ratio 2 (cardinals) : 3 ( chickadees) : 3 ( pigeons). Now before you use the ratio you need to know how many birds out of the 36 have not been seen in the first hour so just subtract 36 - 24 = 12. Next you figure out what number you can multiply every bird against to get a sum of 12 birds in total. I figured out it's 1.5 as a multiplier. I know physically it's not possible, but I did all the steps correct and apparently they don't care it's not realistic. I hope this helps you on the homework sheet.

8 0

3 years ago

According to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation, there were over 71 million wildif

suter [353]

Answer:

The probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is P=0.412.

Step-by-step explanation:

We know the population proportion π=0.8, according to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation.

If we take a sample from this population, and assuming the proportion is correct, it is expected that the sample's proportion to be equal to the population's proportion.

The standard deviation of the sample is equal to:

$\sigma_s=\sqrt{\frac{\pi(1-\pi)}{N}}=\sqrt{\frac{0.8*0.2}{500}}=0.018$

With the mean and the standard deviaion of the sample, we can calculate the z-value for 0.79 and 0.81:

$z=\frac{p-\pi}{\sigma}=\frac{0.79-0.80}{0.018} =\frac{-0.01}{0.018} = -0.55\\\\z=\frac{p-\pi}{\sigma}=\frac{0.81-0.80}{0.018} =\frac{0.01}{0.018} = 0.55$

Then, the probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is:

$P(0.79$

3 0

3 years ago

Simplify 8 (10+3+5v)-2v

Bogdan [553]

I hope this helps you

8.10+8.3+8.5v-2v

80+24+40v-2v

104+38v

7 0

2 years ago