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Varvara68 [4.7K]
2 years ago
7

A student prepares a lactic acid-sodium lactate buffer solution by mixing 40.mL of 0.50MHC3H5O3(aq) with 200.mL of 1.0M NaC3H5O3

(aq) . The pKa of HC3H5O3 is 3.08. What is the pH of the resulting solution?
Chemistry
1 answer:
notsponge [240]2 years ago
8 0

Answer:

pH=3.38

Explanation:

We are given the concentrations of the weak acid and its conjugate base so we need to use the henderson hasslebalch equation

pH=pKa + log (concentration A-/concentration of HA)

A- : conjugate base NaC3H5O3

HA: weak acid HC3H5O3

so if we plug in what we are given

pH= 3.08 + log (1M/.5M)

pH= 3.38

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Element X had a mass of 300g and a 1/2 life of 10 years. how many grams will remain after 40 years?
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<h3>Answer:</h3>

18.75 grams

<h3>Explanation:</h3>
  • Half-life refers to the time taken by a radioactive material to decay by half of the original mass.
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Remaining mass = Original mass × (1/2)^n, where n is the number of half-lives

Number of half-lives = Time for the decay ÷ Half-life

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Therefore;

Remaining mass = 300 g × (1/2)⁴

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