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RoseWind [281]
3 years ago
13

Yo answer my question

Chemistry
2 answers:
Mazyrski [523]3 years ago
5 0

Answer:

Its D

Explanation:

im a pro

igomit [66]3 years ago
3 0

Answer:

C maybe

Explanation:

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A sample of gas has an initial volume of 3.88 l at a pressure of 707 mmhg . part a if the volume of the gas is increased to 5.43
JulsSmile [24]
Using boyles law
p1v1=p2v2
v1=3.88
v2=5.43
p1=707
p2=?
707x3.88=p2x5.43
2743.16/5.43=p2
p2=505mmHg
4 0
3 years ago
Describe how the size of sediment particles affects their movement during deflation.
lutik1710 [3]
The larger the piece the longer it will take to break down. This is because it has more mass that needs to be broken down. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
7 0
3 years ago
Read 2 more answers
Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu
ad-work [718]

Initial volume of the balloon = V_{1}= 348 mL

Initial temperature of the balloon T_{1} = 25.0^{0}C + 273 = 298 K

Final volume of the balloon V_{2} = 322 mL

Final temperature of the balloon = T_{2} = ?

According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.

\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }

On plugging in the values,

\frac{348mL}{298 K} =\frac{322 mL}{T_{2} }

T_{2} =276 K

Therefore, the temperature of the freezer is 276 K

5 0
3 years ago
"What is the change of entropy for 3.0 kg of water when the 3.0 kg of water is changed to ice at 0"
Artyom0805 [142]

Q: What is the change of entropy for 3.0 kg of water when the 3.0 kg of water is changed to ice at 0 °C? (Lf = 3.34 x 105 J/kg)

Answer:

-3670.33 J/K

Explanation:

Entropy: This can be defined as the degree of randomness or disorderliness of a substance. The S.I unit of Entropy is J/K.

Mathematically,  change of Entropy can be expressed as,

ΔS = ΔH/T ....................................... Equation 1

Where ΔS = Change of entropy, ΔH = heat change, T = temperature.

ΔH = -(Lf×m).................................... Equation 2

Note: ΔH is negative because heat is lost.

Where Lf = latent heat of ice = 3.34×10⁵ J/kg, m = 3.0 kg, m = mass of water = 3.0 kg

Substitute into equation

ΔH = -(3.34×10⁵×3.0)

ΔH = - 1002000 J.

But T = 0 °C = (0+273) K = 273 K.

Substitute into equation 1

ΔS = -1002000/273

ΔS = -3670.33 J/K

Note: The negative value of ΔS shows that the entropy of water decreases when it is changed to ice at 0 °C

4 0
3 years ago
Wat is significant figures
Sav [38]

<em>Answer:</em>

  •                   0.052301 km have 5 significant figure
  •                   400 cm have 1 significant figure
  •                   50.0 m  have 3 significant figure
  •                  4500.01 ml have 6 significant figure

<em>Explanation:</em>

According to rules of significant figure

0.052301 km have 5 significant figure:

  • Zero to the left of the first non zero digit not significant.
  • Zero between the non zero digits are significant.

<em>400 cm have 1 significant figure:</em>

  • Trailing zeros are not significant in numbers without decimal points.

<em>50.0 m  have 3 significant figure:</em>

  • Trailing zeros are significant in numbers when there is decimal points.

<em>4500.01 ml have 6 significant figure:</em>

  • Zero between the non zero digits are significant.
4 0
4 years ago
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