Answer:
Molar mass of NaHCO3 = 84.00661 g/mo
Explanation:
This compound is also known as Baking Soda or Sodium Bicarbonate.
Convert grams NaHCO3 to moles or moles NaHCO3 to grams
Molecular weight calculation:
22.98977 + 1.00794 + 12.0107 + 15.9994*3
The fact that the student used different amount of water (another independent variable) is wrong with the experimental design
WHAT ARE THE COMPONENTS OF AN EXPERIMENT?
- An experiment aims at solving a scientific problem or answering a scientific question. An experiment should contain a variable being changed called INDEPENDENT VARIABLE and a variable being measured called DEPENDENT VARIABLE.
- In an ideal experiment, only one independent variable should be used while every other variable should be kept constant. This is done so as not to affect the result of the experiment.
In the experiment conducted by the student in this question, two independent variables were used i.e. the different amount of water and the different temperatures. This is what is wrong about the experimental design.
- In a nutshell, the fact that two independent variables were used by the student is what is wrong about the experimental design.
Learn more at: brainly.com/question/967776
Acids or bases<span> with weak bonds easily dissociate into ions and are called "</span>strong<span>" acids or </span>bases<span>. Table 1: Summary List of </span>Characteristics<span> for </span>Strong<span> and Weak Acids and </span>Bases<span>. All </span>characteristics<span> of acids and </span>bases<span> are related to whether the predominate forms are molecules and ions. </span>Characteristic<span>.</span>
Answer:
Kp = 8.76×10⁻³
Explanation:
We determine the carbamate decomposition in equilibrium:
NH₄CO₂NH₂ (s) ⇄ 2NH₃(g) + CO₂(g)
Let's build the expression for Kp
Kp = (Partial pressure NH₃)² . Partial pressure CO₂
We do not consider, the carbamate because it is solid and we only need the partial pressure from gases
Kp = (0.370atm)² . 0.0640 atm
Kp = 8.76×10⁻³
Remember Kp does not carry units
Answer:
65.21 percent
Explanation:
We are to find the percentage yield
We have this equation,
2no+o2 -->2no2
Such that 1500 kilograms/30grams
= Mno2/46
=1500/30 = mno2/46
We cross multiply from here
1500x46 = 30xMnO2
69000 = 30Mno2
69000/30 = MnO2
2300 = Mno2
The percentage yield would be
1500/2300 *100
= 0.6521 x 100
= 65.21%
This answers the question
