Answer: 77.47 g of will be produced from 100.0 g of Iron (III) hydroxide
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
2 moles of produce = 1 mole of
Thus 0.935 moles of will producee= of
Mass of
Thus 77.47 g of will be produced from 100.0 g of Iron (III) hydroxide
Answer:
4)less electron
Explanation:
A K+ ion still has the same nuclus but due to a loss of an electron which is negativly charged the K atom becomes a K+ ion.
Answer:
Boiling point of the solution is 100.78°C
Explanation:
This is about colligative properties.
First of all, we need to calculate molality from the freezing point depression.
ΔT = Kf . m . i
As the solute is nonelectrolyte, i = 1
0°C - (-2.79°C) = 1.86 °C/m . m . 1
2.79°C / 1.86 m/°C = 1.5 m
Now, we go to the boiling point elevation
ΔT = Kb . m . i
Final T° - 100°C = 0.52 °C/m . 1.5m . 1
Final T° = 0.52 °C/m . 1.5m . 1 + 100°C → 100.78°C
<span>The region(s) of the periodic table which are
made up of elements that can adopt both positive and negative oxidation numbers
are the “non-metal” region. As we can see on the periodic table, the elements situated
at the right side of the table have two oxidation states, one positive and the
other a negative. </span>
Answer:
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