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katen-ka-za [31]

3 years ago

9

The floor plan of a proposed auditorium shows a stage that measures 1.75 inches in width. The scale of the floor plan is 1in. =

18 ft. What is the width of the proposal stage?

1 answer:

Darya [45]3 years ago

6 0

Can you make the picture more clear

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Rewrite 9cos 4x in terms of cos x.

rosijanka [135]

$\bf \qquad \textit{Quad identities}\\\\
sin(4\theta )=
\begin{cases}
8sin(\theta )cos^3(\theta )-4sin(\theta )cos(\theta )\\
4sin(\theta )cos(\theta )-8sin^3(\theta )cos(\theta )
\end{cases}
\\\\\\
cos(4\theta)=8cos^4(\theta )-8cos^2(\theta )+1\\\\
-------------------------------\\\\
9cos(4x)\implies 9[8cos^4(x)-8cos^2(x)+1]
\\\\\\
72cos^4(x)-72cos^2(x)+9$

---------------------------------------------------------------------------

as far as the previous one on the 2tan(3x)

$\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\qquad tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}\\\\
-------------------------------\\\\$

$\bf 2tan(3x)\implies 2tan(2x+x)\implies 2\left[ \cfrac{tan(2x)+tan(x)}{1-tan(2x)tan(x)}\right]
\\\\\\
2\left[ \cfrac{\frac{2tan(x)}{1-tan^2(x)}+tan(x)}{1-\frac{2tan(x)}{1-tan^2(x)}tan(x)}\right]\implies 2\left[ \cfrac{\frac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}}{\frac{1-tan(x)-2tan^3(x)}{1-tan^2(x)}} \right]
\\\\\\$

$\bf 2\left[ \cfrac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}\cdot \cfrac{1-tan^2(x)}{1-tan(x)-2tan^3(x)} \right]
\\\\\\
2\left[ \cfrac{3tan(x)-tan^3(x)}{1-tan^2(x)-2tan^3(x)} \right]\implies \cfrac{6tan(x)-2tan^3(x)}{1-tan^2(x)-2tan^3(x)}$

4 0

3 years ago

Help, need answer, and work for the problem/will only take a sec please!!!!!!

suter [353]

Answer:

18 inches

Step-by-step explanation

equating the 2 gives

2πr=36π

divide both sides by

2π

radius r=18 inches

8 0

3 years ago

Read 2 more answers

Nonamiya [84]

Answer:

y = -1/2x + 3.5

Step-by-step explanation:

The gradients of perpendicular lines multiply to make -1. The gradient of the line given is 2, so 2 multiplied by something gives us -1. 2 × -1/2 = -1. The gradient of the perpendicular line is -1/2

y = -1/2x + c

Now we can substitute x = 1 and y = 3 into the equation:

3 = -1/2(1) + c
3 = -1/2 + c
c = 3 + 1/2
c = 3 1/2 or 3.5 or 7/2

The equation of the line is y = -1/2x + 3.5

Hope this helps!

3 0

3 years ago

What is b PLSSSS ANSWER<br> WILL GIVE BRAINLIEST

Ket [755]

Answer: -15 divided by 0.3 is the same as -15/3/10 but to solve we can do -15 times 10/3 witch is -150/3=-50

Step-by-step explanation:

3 0

3 years ago

How do you find volume?

Naddik [55]

Answer:

Length x Width x Height

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers