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1 year ago

Write the equation of a line that passes through the point (-8,4) and is parallel to the line y=-5x+3.

Mathematics

1 answer:

Oduvanchick [21]1 year ago

5 0

Answer: y=-5x-36

Step-by-step explanation:

In order for two lines to be parallel they need to have the same slope. so the slope (m) of the new line needs to be -5.

slope(m) =-5

and the point (-8,4) is given to us. we can create a new equation for a line using the point slope formula because we have a slope (m=-5) and a point (-8,4)

point slope formula: y-y1=m(x-x1)

y-4=-5(x--8)

simplify and pay attention to negative signs

y-4=-5(x+8)

y-4=-5x-40

y=-5x-36

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Given m||n, find the value of x

Salsk061 [2.6K]

Answer:

x = 155º

Step-by-step explanation:

y = 25° {Vertically opposite angles}

x + y = 180 {Co-interior angles are supplementary}

x + 25 = 180

Subtract 25 from both sides

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2 years ago

What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?

joja [24]

Answer:

23rd term of the arithmetic sequence is 118.

Step-by-step explanation:

In this question we have been given first term a1 = 8 and 9th term a9 = 48

we have to find the 23rd term of this arithmetic sequence.

Since in an arithmetic sequence

$T_{n}=a+(n-1)d$

here a = first term

n = number of term

d = common difference

since 9th term a9 = 48

48 = 8 + (9-1)d

8d = 48 - 8 = 40

d = 40/8 = 5

Now $T_{23}= a + (n-1)d$

= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118

Therefore 23rd term of the sequence is 118.

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3 years ago

Help with unknown angle measure (view image linked)

fenix001 [56]

Answer:

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Step-by-step explanation:

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2 years ago

Calculate the Highest common factor of 130,260,390

qwelly [4]

the Highest common factor of 130,260,390 = 130

130 = 2⋅5⋅13

260 = 2⋅2⋅5⋅13

390 = 2⋅3⋅5⋅13

Common multipliers (130; 260; 390): 2, 5, 13

Now to find the highest Common factor you need to multiply the common factors

Answer: (130 ; 260 ; 390) = 2 ∙ 5 ∙ 13 = 130

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2 years ago

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3 years ago

Write the equation of a line that passes through the point ​(-8​,4​) and is parallel to the line y=-5x+3.

Write the equation of a line that passes through the point (-8,4) and is parallel to the line y=-5x+3.