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3 years ago

6

Elena's math class had 25 students yesterday. she miscounted the class total and recorded it as 20 students. What is Elena's per

cent error ?

1 answer:

adelina 88 [10]3 years ago

8 0

Elena had a 5% error

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Give the “best” big-oh notation to describe the complexity of the algorithm that prints all bit strings of length n.

artcher [175]

It is correct to state that a bit can be in one of 2 states, either 1 or 0.

<h3>What is a bit?</h3>

A bit is is a single binary digit. A bit can either be "1" or "0".

<h3>What is the explanation to the above answer?</h3>

We stated that It is correct to indicate that a bit can be in one of 2 states, either 1 or 0. This indicates that 2ⁿ strings must be created in total. The string must then be processed twice.

The first time, for generation and
The second for reading.

Hence, Our time is now O(2ⁿ⁺¹) = O(2ⁿ)

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4 0

3 years ago

Suppose you earned $15 from your job last week. You want to save $3 and buy

Rina8888 [55]

15$ .. 3$ 12 more dollars left - you can only buy 3 boooks !

3 0

3 years ago

The graph of f(x)=20(0.5)x is shown.

svp [43]

Answer:

C) f(2) = 5

Step-by-step explanation:

f(2) = 20(0.5)*2

f(2) = 2(10)

f(2) = 20

f(2) = 20 ≠ f(2) = 5

6 0

3 years ago

Pulse rates (in beats per minute) were collected on a sample of 36 men. The five number summary for the data is as follows: Lo:

algol13

Answer:

27 men had a pulse rate between 56 & 100.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 36

Five number summary:

Lowest value: 56

Lower Quartile: 71

Median: 80

Upper Quartile: 100

Highest value: 140

We have to find the number of men that had a pulse rate between 56 & 100.

56 is the lowest value of data and 100 is the third quartile of data.

Now, the third quartile give 75 percentile of data, thus, 75% of data lies between lowest value and the third quartile.

Thus, 75% of men have a pulse rate between 56 & 100.

Number of men that had a pulse rate between 56 & 100 =

$75\% \times n\\\\=\dfrac{75}{100}\times 36 = 27$

Thus, 27 men had a pulse rate between 56 & 100.

6 0

3 years ago

What is a counterexample to this claim?

yan [13]

Answer: B
Explanation: 9 is the only odd number meaning it’s contradicting the claim that all perfect squares are even since 9 isn’t even. a 3x3 square would be 9 but its also perfect explaining how not all perfect squares are even.

5 0

3 years ago