Set up a system of equations:
2x+3y=6
x-3y=9
You can solve this with elimination by adding the two equations together:
3x+0y = 15
3x=15
x=5
Then, plug this value back into either of the original equations to find the y value:
5-3y=9
-3y=4
y= -4/3
The point of intersection is (5,-4/3)
Answer:
39.17% probability that a woman in her 60s who has a positive test actually has breast cancer
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Positive test.
Event B: Having breast cancer.
3.65% of women in their 60s get breast cancer
This means that 
A mammogram can typically identify correctly 85% of cancer cases
This means that 
Probability of a positive test.
85% of 3.65% and 100-95 = 5% of 100-3.65 = 96.35%. So
What is the probability that a woman in her 60s who has a positive test actually has breast cancer?
39.17% probability that a woman in her 60s who has a positive test actually has breast cancer
Answer:
76 on second exam, 80 on third exam
Step-by-step explanation:
First, find the total of all 3 test scores by multiplying the average by the number of elements. 81 · 3 = 243.
The first score is 83 so 243 - 83 = 160. 160 is the other two test scores combined.
To find the other 2 scores, divide 160 by 2, which is 80.
The second score is 4 less so it will be 76. The third score is 80.
That would be C because there are two zeros right?
So you move two decimal places from 67.
And you get 0.67
Answer:
Step-by-step explanation:
a) (a + b)² = (a + b) * (a +b)
(a + b)³ = (a + b) * (a +b) * (a +b)
a²- b² = (a +b) (a - b)
Here (a + b) is common in all the three expressions
HCF = (a + b)
b) (x - 1) = (x - 1)
x² - 1 = (x - 1) * (x + 1)
(x³ - 1) = (x - 1) (x² + x + 1)
HCF = (x -1)
