(-8)/(2y-8)=(5/(y+4))-7y+(8/(y^2-16))
(-4)/(y-4)=(5/(y+4))-7y+(8/(y+4)(y-4))
((-4)(y+4))/((y+4)(y-4))=((5(y-4))/(y+4)(y-4))-(7y(y+4)(y-4))/(y+4)(y-4))+(8/(y+4)(y-4))
(-4(y+4))=(5(y-4))-(7y(y+4)(y-4))+8
-4y-16=5y-20-(7y(y^2-16))+8
-4y-16=5y-20-7y^3+112y+8
-4y-16=117y-7y^3-12
-4=(121-7y^2)(y)
None of these choices would be equal to -4
They areall related to geoemtry
Answer:
Choice A
Step-by-step explanation:
(4m^5n^2/m^2n)^3
dividing exponents = subtraction
(4m^3n)^3
4^3 = 64
(m^3 )^3 = m^3x3 = m^9
64m^9n^3
sorry misread the question
Answer:
10.8 minutes
Step-by-step explanation:
Given data
We are told that the number of Jugs is 18
Filling the first 3 jugs has taken 5 minutes
let us find the filling rate
Rate= 3/5
Rate= 0.6 Jugs per minute
Hence the rate of filling is 0.6 Jugs per minute
Therefore the time take to fill the remaining 16 jugs is
TIme= Rate*Number of Jugs
TIme= 0.6*18
Time= 10.8 minutes
