The quadratic equation has two solutions if b^2 - 4ac > 0
Given the equation ax^4 + bx^2 + c=0
Substitute into the formula to have:
The equation becomes aP^2 + bP + c = 0
For us to have a unique solution, the discriminant b^2 - 4ac must be greater than zero. Hence the quadratic equation has two solutions if b^2 - 4ac > 0
learn more on discriminant here; brainly.com/question/1537997
Answer:
Angle = Ф =
(0) = 0
Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.
Step-by-step explanation:
Given vector r(t) = 
As we know that,
velocity vector = v = 
Implies that
velocity vector = 
As acceleration is velocity over time so:
acceleration vector = a = 
Implies that
vector a =

vector a = 
Now scalar product of position vector r and acceleration vector a:
r. a = 
r.a = 
r.a = 0
Now, for angle between position vector r and acceleration vector a is given by:
cosФ =
= 
Ф =
(0) = 0
Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.
Remove the radical by raising each side
6^2= square root 8x-4 ^2
36= 8x-4
40= 8x
X=5
The formula of a slope:

We have the points (-2, -2) and (-4, 1). Substitute:

<h3>Answer: slope =

</h3>
Answer:
x = 83 degrees
Step-by-step explanation:
35 + 28 = 63
63 + 34 = 97
180 - 97 = 83