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TEA [102]
3 years ago
5

Type the correct answer in the box.

Mathematics
2 answers:
MissTica3 years ago
6 0
The answer is 10 square unit
Serjik [45]3 years ago
4 0

Answer:

I think the answer is 10 square units

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Ax4 + bx2 + c=0 (a>0) (c>0)
Irina18 [472]

The quadratic equation has two solutions if b^2 - 4ac > 0

Given the equation ax^4 + bx^2 + c=0

  • Let P = x^2

Substitute into the formula to have:

  • a(x^2)^2 + bx^2 + c =0

The equation becomes aP^2 + bP + c = 0

For us to have a unique solution, the discriminant b^2 - 4ac must be greater than zero. Hence the quadratic equation has two solutions if b^2 - 4ac > 0

learn more on discriminant here; brainly.com/question/1537997

4 0
3 years ago
Suppose r(t) = (et cos t)i + (et sin t)j. Show that the angle between r and a never changes. What is the angle?
tatyana61 [14]

Answer:

Angle = Ф = cos^{-1}(0) = 0

Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.

Step-by-step explanation:

Given vector r(t) = e^{t}cost i + e^{t}sint j

As we know that,

velocity vector = v = \frac{dr}{dt}

Implies that

velocity vector = (e^{t} cost - e^{t} sint)i + (e^{t} sint - e^{t}cost )j

As acceleration is velocity over time so:

acceleration vector = a = \frac{dv}{dt}

Implies that

vector a =

(e^{t}cost - e^{t}sint - e^{t}sint - e^{t}cost )i + ( e^{t}sint + e^{t}cost + e^{t}cost - e^{t}sint )j

vector a = (-2e^{t}sint) i + ( 2e^{t}cost)j

Now scalar product of position vector r and acceleration vector a:

r. a = . \\

r.a = -2e^{2t}sintcost + 2e^{2t}sintcost

r.a = 0

Now, for angle between position vector r and acceleration vector a is given by:

cosФ = \frac{r.a}{|r|.|a|} = \frac{0}{|r|.|a|} = 0

Ф = cos^{-1}(0) = 0

Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.

4 0
3 years ago
Solve radical equation
xeze [42]
Remove the radical by raising each side

6^2= square root 8x-4 ^2

36= 8x-4

40= 8x

X=5
6 0
4 years ago
Read 2 more answers
What is the slope of (-2,-2) and (-4,1)
FinnZ [79.3K]

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-2, -2) and (-4, 1). Substitute:

m=\dfrac{1-(-2)}{-4-(-2)}=\dfrac{1+2}{-4+2}=\dfrac{3}{-2}=-\dfrac{3}{2}

<h3>Answer: slope = -\dfrac{3}{2}</h3>
5 0
3 years ago
Read 2 more answers
HailyDenney2 I need your assistance please!
Marina86 [1]

Answer:

x = 83 degrees

Step-by-step explanation:

35 + 28 = 63

63 + 34 = 97

180 - 97 = 83

6 0
3 years ago
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