Write the linear equation in slope intercept form from passing through the point with the given slope (-5,-3);slope =-3/5
1 answer:
You might be interested in
Answer:
63.25sqft
Step-by-step explanation:
semi circle:
a=r^2
a=(5)^2 (radius is 5 bc diameter is 10 so you divide it by 2)
a=25
a=78.5/2=39.25 (divide by 2 bc its a semi circle)
triangle:
a=1/2bh
a=1/2(6x8)
a=1/2(48)
a=24
area:
39.25+24=63.25
Answer:
The reason why this equation can not be written in the slope-intercept form because the slope of this line is undefined.
Step-by-step explanation:
We know the slope-intercept form of line equation is
y = mx+b
where m is the slope and b is the y-intercept
Given the points
- (-8,-5)
- (-8,-9)
Finding the slope between (-8,-5) and (-8,-9)
(x₁, y₁) = (-8,-5)
(x₂, y₂) = (-8,-9)
slope = m = (y₂-y₁) / (x₂-x₁)
= -9 - (-5) / -8 - (-8)
= -9+5 / -8+8
= -4 / 0
= ∞
Thus, the slope = m = ∞
- The reason why this equation can not be written in the slope-intercept form because the slope of this line is undefined.
In other words, whatever the value of y is, the x-value always remains constant.
In other words, the line will be vertical and the slope of a vertical line will be undefined.
Thus, the equation of this line is:
x = -8
The line graph is also attached.
Therefore, the reason why this equation can not be written in the slope-intercept form because the slope of this line is undefined.
