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Kazeer [188]
2 years ago
12

A dump truck pours sand into a container in the shape of a rectangular prism with a square base of length 2 feet. The height, h,

of the sand in the container increases at a rate of approximately 8 inches per minute. Create an equation that models the volume, V, of the sand in the container in terms of h, then use the equation to determine the time at which the volume is 64 cubic feet. Note that the volume of a rectangular prism is V=l×w×h, where l, w, and h are the length, width, and height of the prism.
Mathematics
2 answers:
ser-zykov [4K]2 years ago
6 0

Answer:6+89

Step-by-step explanation:439+3947+v=90

aev [14]2 years ago
5 0

Answer:

I think the answer is 24 minutes!

Step-by-step explanation:

I hope this helps!

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A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

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3 years ago
What is the slope of the line y = -2?
rjkz [21]

Answer:

slope= 0

Step-by-step explanation:

it's a horizontal line

4 0
3 years ago
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