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nalin [4]
3 years ago
6

A person invests 9000 dollars in a bank. The bank pays 4.75% interest compounded quarterly. To the nearest tenth of a year, how

long must the person leave the money in the bank until it reaches 12600 dollars?
Mathematics
2 answers:
solong [7]3 years ago
8 0

7.1 years

Step-by-step explanation:

Principle P = 9000 dollars

Rate r = 4.75% = 0.0475

Total Amount A = 12600 dollars

compounded quarterly n = 4

Time t = ?

t = ln(A/P) / n[ln(1 + r/n)]

t = ln(12,600/9,000) / ( 4 × [ln(1 + 0.011875/4)] )

t = 7.1 years

so the answer is 7.1 years

sukhopar [10]3 years ago
7 0
The answer is 7.1 because the answer is 7.1
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Let's assume the following data:

Price in Dollars (X) 26 29 32 38 47

Number of Bids (Y) 12 13 15 16 18

For our case we have this:

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Step-by-step explanation:

Previous concepts

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

Solution to the problem

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

Let's assume the following data

Price in Dollars (X) 26 29 32 38 47

Number of Bids (Y) 12 13 15 16 18

For our case we have this:

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