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2 years ago

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The table displays the mean for seven random samples. Sample Sample Mean 1 23.2 2 26.7 3 24.9 4 24.6 5 28.0 6 26.3 7 23.4 Which

value is the best estimate of the mean of the population? 22.9 24.2 28.2 29.1

2 answers:

madam [21]2 years ago

6 0

Answer:

24.2 B

Step-by-step explanation:

This is right on edge

alukav5142 [94]2 years ago

4 0

Answer:

24.2

Step-by-step explanation:

I took the quiz and got it right

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The SAT scores have an average of 1200 with a standard deviation of 60. A sample of 36 scores is selected. a) What is the probab

erastova [34]

Answer:

the probability that the sample mean will be larger than 1224 is 0.0082

Step-by-step explanation:

Given that:

The SAT scores have an average of 1200

with a standard deviation of 60

also; a sample of 36 scores is selected

The objective is to determine the probability that the sample mean will be larger than 1224

Assuming X to be the random variable that represents the SAT score of each student.

This implies that ;

$S \sim N ( 1200,60)$

the probability that the sample mean will be larger than 1224 will now be:

$P(\overline X > 1224) = P(\dfrac{\overline X - \mu }{\dfrac{\sigma}{\sqrt{n}} }> \dfrac{}{}\dfrac{1224- \mu }{\dfrac{\sigma}{\sqrt{n}} })$

$P(\overline X > 1224) = P(Z > \dfrac{1224- 1200 }{\dfrac{60}{\sqrt{36}} })$

$P(\overline X > 1224) = P(Z > \dfrac{24 }{\dfrac{60}{6} })$

$P(\overline X > 1224) = P(Z > \dfrac{24 }{10} })$

$P(\overline X > 1224) = P(Z > 2.4 })$

$P(\overline X > 1224) =1 - P(Z \leq 2.4 })$

From Excel Table ; Using the formula (=NORMDIST(2.4))

P(\overline X > 1224) = 1 - 0.9918

P(\overline X > 1224) = 0.0082

Hence; the probability that the sample mean will be larger than 1224 is 0.0082

4 0

3 years ago

Two sets of 4 consecutive positive integers have exactly one integer in common. The sum of the integers in the set with greater

soldi70 [24.7K]

If you have two sets of integers {1, 2, 3, 4} and {4, 5, 6, 7}, then the sum of each set is 10 and 22, respectively, with a difference of 12. Based on logic, we know that this applies to any numbers you choose that meet the criteria. Number theory offers a more formalized outlook on these concepts.

The answer is D.

8 0

3 years ago

Read 2 more answers

Use the rational zero theorem to create a list of all possible rational zeros of the function f(x)=14x7-4x2+2

frosja888 [35]

Answer:

Factor this polynomial:

F(x)=x^3-x^2-4x+4

Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3).

The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you find that the roots are at

x = 1, x = 2 and x = -2. This means that

x^3-x^2-4x+4 = A(x - 1)(x - 2)(x + 2)

A = 1, as you can see from equation the coefficient of x^3 on both sides.

Typo:

The rational roots can be

+/-1, +/-2 and +/-4

Step-by-step explanation:

6 0

3 years ago

If the distance covered by an object in time t is given by s(t)=t^2+5t , where s(t) is in meters and t is in seconds, what is th

alisha [4.7K]

Answer:

E. 44 meters

Step-by-step explanation:

The function that models the distance covered by the object is

$s(t)=t^2+5t$

where s(t) is in meters and t is in seconds.

The distance covered by the object after 1 second is

$s(1)=1^2+5(1)=6m$

The distance covered by the object after 1 second is

$s(1)=5^2+5(5)=50m$

The distance covered between 1 second and 5 seconds is

50-6=44m

6 0

3 years ago

In a survey of 300 T.V. viewers, 40% said they watch network news programs. Find the margin of error for this survey if we want

bixtya [17]

Answer:

<h2>0.05543</h2>

Step-by-step explanation:

The formula for calculating the margin of error is expressed as;

$M.E = z * \sqrt{\frac{p*(1-p)}{n} }$ where;

z is the z-score at 95% confidence = 1.96 (This is gotten from z-table)

p is the percentage probability of those that watched network news

p = 40% = 0.4

n is the sample size = 300

Substituting this values into the formula will give;

$M.E = 1.96*\sqrt{\frac{0.4(1-0.4)}{300} }\\ \\M.E = 1.96*\sqrt{\frac{0.4(0.6)}{300} }\\\\\\M.E = 1.96*\sqrt{\frac{0.24}{300} }\\\\\\M.E = 1.96*\sqrt{0.0008}\\\\\\M.E = 1.96*0.02828\\\\M.E \approx 0.05543$

Hence, the margin of error for this survey if we want 95% confidence in our estimate of the percent of T.V. viewers who watch network news programs is approximately 0.05543

5 0

3 years ago