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2 years ago

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The table displays the mean for seven random samples. Sample Sample Mean 1 23.2 2 26.7 3 24.9 4 24.6 5 28.0 6 26.3 7 23.4 Which

value is the best estimate of the mean of the population? 22.9 24.2 28.2 29.1

2 answers:

madam [21]2 years ago

6 0

Answer:

24.2 B

Step-by-step explanation:

This is right on edge

alukav5142 [94]2 years ago

4 0

Answer:

24.2

Step-by-step explanation:

I took the quiz and got it right

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Can someone plz solve!!!??????

Tju [1.3M]

To find q + 3, you need to answer this first:

What is 5-3?

5-3=2.

q would be equal to 2.

so now we have something like this:

1
_ ( 2 + 3) =5

3

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3 years ago

Read 2 more answers

Sloan [31]

Answer:

D. Car B was 10 miles east of car A

Step-by-step explanation:

→ Work out how many miles car A travelled

130

→ Work out how many miles car B travelled in 2 hrs

120

→ Find the difference

Car A is bigger by 10 miles

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2 years ago

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(ii) Hence solve the following system of simultaneous equations:

gladu [14]

Answer:

Hi how are you doing today Jasmine

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3 years ago

What is equivalent to<br> 4(b+5)

topjm [15]

4b+20 because you disrepute the 4

6 0

3 years ago

The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped

kakasveta [241]

Check the picture below.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}$

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

$\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}$

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill$

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0

3 years ago