X= 2.5 2.75 divided by 1.10 =2.5
Step-by-step explanation:
For a quadratic equation y = ax² + bx + c, the vertex (the maximum or minimum point) is at x = -b/(2a).
1) y = -0.5t² + 2t + 38
The maximum is at:
t = -2 / (2 × -0.5)
t = 2
The maximum height is:
y = -0.5(2)² + 2(2) + 38
y = 40
The coordinates of the vertex are (2, 40). That means the missile reaches a maximum height of 40 km after 2 minutes.
2) y = -4.9t² + 12t + 1.6
The maximum is at:
t = -12 / (2 × -4.9)
t = 1.22
The maximum height is:
y = -4.9(1.22)² + 12(1.22) + 1.6
y = 8.95
The coordinates of the vertex are (1.22, 8.95). That means the missile reaches a maximum height of 8.95 m after 1.22 seconds.
3) y = -0.04x² + 0.88x
The maximum is at:
x = -0.88 / (2 × -0.04)
x = 11
The maximum height is:
y = -0.04(11)² + 0.88(11)
y = 4.84
The maximum height of the tunnel is 4.84 meters.
The maximum width is when y = 0.
0 = -0.04x² + 0.88x
0 = -0.04x (x − 22)
x = 22
The maximum width is 22 feet.
Positive numbers is the last one
Answer:
1 . Segment EF is twice as as segment AB
4. The length of segment EH is 16 units
Step-by-step explanation:
Quadrilateral EFGH was created by increasing all the length segments of quadrilateral ABCD proportionally by multiplying the lengths of ABCD by a scale factor.
Scale factor used = GH/CD = 12/6 = 2
Let's examine each statements to see which is true or not true:
1 . "Segment EF is twice as as segment AB."
This is true. EF corresponds to AB. Since scale factor = 2, length of any segment of quadrilateral EFGH would be twice the length of quadrilateral ABCD.
2. "Segment CD is twice as long as segment FG."
This is not true, because segment CD does not correspond to segment FG. Segments in EFGH are twice as the corresponding segments in ABCD.
3. "The measure of angle HEF is twice the measure of the angle DAB."
This is not true. Shape remains the same. Only the size changes.
4. "The length of segment EH is 16 units".
This is true because EH is twice the corresponding segment in ABCD, which is 2"AD = 2*8 = 16 units.
5. "The area of EFGH is twice the are of ABCD"
This is not true. Area of the scaled copy would be times 4 of the original figure.
Answer:
<BCE=76
Step-by-step explanation:
<BCD-<ECD=<BCE
147-71=76
