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3 years ago

PLEASE HELP ME

Mathematics

1 answer:

defon3 years ago

8 0

Answer:

(x+5) (x-3)

Step-by-step explanation:

5 times -3= -15

5 + -3 = 2

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find the value of x. Round to the nearest degree

Aleksandr-060686 [28]

Answer:

51 degress

Step-by-step explanation:

sin x = 7/9

x = sin^-1 (7/9)

simply using a calculator.

3 0

3 years ago

Read 2 more answers

9. The ages of A and B are in the ratio 3:5. Four years later,

Tom [10]

Answer:

A = 15 B = 25 in four years 19+29 = 48

Step-by-step explanation:

age A and B ratio is 3 to 5

A+4 + B+4 = 48

A + B = 40

A/B = 3/5 A = 3B/5

A + B = 40

3B/5 + B = 40

3B + 5B = 200 multiple both sides by 5

8B = 200

B = 25

A = 3B/5

A = 3(25)/5

A = 15

8 0

3 years ago

Read 2 more answers

A countries population in 1991 was 147 million. In 1998 it was 153 million. Estimate the population in 2017 using the exponentia

scoundrel [369]

Answer:

The population in 2017 is 171 million

Step-by-step explanation:

Let's assume population starts from 1991

so,

initial population is 147 million

so, $A=147$

we can use formula

$P=Ae^{kt}$

we can plug A=147

$P=147e^{kt}$

In 1998:

t=1998-1991=7

$P=153$

now, we can plug these values into formula and find k

$153=147e^{7k}$

Divide both sides by 147

$\frac{147e^{7k}}{147}=\frac{153}{147}$

$e^{7k}=\frac{51}{49}$

$\ln \left(e^{7k}\right)=\ln \left(\frac{51}{49}\right)$

$k=\frac{\ln \left(\frac{51}{49}\right)}{7}$

$k=0.00572$

now, we can plug it back

and we get

$P=147e^{0.00572t}$

In 2017:

t=2017-1991=26

we can plug it and find P

$P=147e^{0.00572\times 26}$

$P=170.57$

So,

The population in 2017 is 171 million

5 0

3 years ago

What's the difference between a number divided by three and four is twenty into an equation

Schach [20]

Yes Ther ya go ncalnflanfla

8 0

2 years ago

Factorise 2x^3+9x^2+10x+3

Advocard [28]

In order to factor a polynomial $p(x)$ , we have to find all its roots $x_1,\ x_2,\ldots x_n$ so that we can rewrite the polynomial as

$p(x)=(x-x_1)(x-x_2)\ldots(x-x_n)$

This is exactly the same idea we apply when we factor numbers: we look for all the primes that divide the number, and then we write

$n = p_1^{e_1}\cdot p_2^{e_2}\ldots p_n^{e_n}$

When talking about polynomials, the idea of prime numbers is represented by irreducible polynomials, i.e. polynomials with no roots.

So, we have to find a root of our polynomial. Using the rational root theorem, we can check that $x=-1$ is a solution:

$p(-1)=2(-1)^3+9(-1)^2+10(-1)+3 = -2+9-10+3=0$

So, our polynomial is divisible by $(x+1)$ . The long division yields

$\dfrac{2x^3+9x^2+10x+3}{x+1} = 2x^2+7x+3$

Which is the same as

$2x^3+9x^2+10x+3=(x+1)(2x^2+7x+3)$

We can complete the factorization by breaking the quadratic equation: using the standard quadratic formula we can find the solutions

$2x^2+7x+3=0 \iff x=-\dfrac{1}{3}\text{ or }x=-3$

Which implies

$2x^2+7x+3=\left(x+\dfrac{1}{2}\right)(x+3)$

And finally

$2x^3+9x^2+10x+3=(x+1)\left(x+\dfrac{1}{2}\right)(x+3)$

8 0

3 years ago