Answer:
I think the equation that best represent the relationship between r and s is A. s=1/6r
Answer:
0.012
Step-by-step explanation:
Linear approximation says that,
For a cube the surface area is 
.
So the side is 1.0 inch in, the surface area is 
square inches.
In Linear approximation means you ignore the term 
, if 
is a small number, because then will be a very smalle number and that does not contribute much to the error.
So the surface area is approximately,
So here, 
The error in the area is approximately,
So the error is 0.012.
Answer:
Part A
The given numbers are 14.25 and 0.86
By multiplying the two numbers, we have;
14.25 × 0.86 = 12.255
By adding the two numbers, we have;
14.25 + 0.86 = 15.11
Therefore, addition gives the greatest solution because one of the number is a fraction less than one
Part B
By dividing the two numbers (Dividing the larger number, 14.25 by the smaller number 0.86), we have 14.25/0.86 ≈ 16.57
Therefore, dividing the larger number by the smaller fraction gives a solution larger than the solution found in part A because the larger number multiplied by (1 - the inverse smaller fraction number) is larger than the value of the smaller (fraction) number
Step-by-step explanation:
Answer:
C:) 17/3
Step-by-step explanation:
Simplify the following:
((3 + 2/5)×5)/3
((3 + 2/5)×5)/3 = ((3 + 2/5)×5)/3:
((3 + 2/5)×5)/3
Put 3 + 2/5 over the common denominator 5. 3 + 2/5 = (5×3)/5 + 2/5:
((5×3)/5 + 2/5 5)/3
5×3 = 15:
((15/5 + 2/5)×5)/3
15/5 + 2/5 = (15 + 2)/5:
((15 + 2)/5×5)/3
15 + 2 = 17:
(17/5×5)/3
17/5×5 = (17×5)/5:
((17×5)/5)/3
((17×5)/5)/3 = (17×5)/(5×3):
(17×5)/(5×3)
(17×5)/(5×3) = 5/5×17/3 = 17/3:
Answer: 17/3
Answer:
2nd answer option
Step-by-step explanation:
the domain is the interval or set of valid x values. the range is the same for valid y values.
so, what is the smallest x value we see in the functional graph ?
x = 0
there is no functional value for any x smaller than that.
and then the function goes on and on to the right in all eternity. that means it goes to infinity.
so, domain = [0, infinity)
please consider the round bracket at the end, because "infinity" is not a number.
now for the range and the y values.
in this case I start to ask for the largest y value.
y = 4
for no x value do we get a larger y value.
but it goes down and down in all eternity, going also to infinity, but -infinity (down is negative for y).
so, the range = (-infinity, 4]
"-infinity" is also not a number and therefore not included (hence the round bracket).
