6.25
explanation: if you divide 6.25 by 5 you get 1.25, if you divide 17.40 by 12 it’s 1.45. Therefore you pay more.
Answer:
B. He added 3.5 and 5 when he should have multiplied them.
Step-by-step explanation:
Let's observe Joe's steps:
- V = lwh
- 204 = 3.5 * (5) * l
Here, * means to multiply, so we're supposed to multiply 3.5 to 5, which would give you the answer 17.5. Unfortunately, look what Joe got: he obtained the value of 8.5, and if we observe, 3.5 + 5 = 8.5.
That's how we know that Joe added instead of multiplied, as he should have done. Thus, the answer is B.
Answer:
There is a decreasing pattern the farther they are the less likely hit the target.
Step-by-step explanation:
They give the formula as:
Surface Area =<span> (2 • <span>π <span>• r²) + (2 • <span>π • r • height)</span></span></span></span>
However the 2*PI*r^2 part of the formula is used to calculate the 2 "ends" of a cylinder. Since the problem states that you are NOT to count any of surface area of the "ends" then you only need the <span>(2 • <span>π • r • height) part of the formula.
So, r = 3 inches and height = 8 * 3 inches, the side area equals
2 * PI * r * height
2 * 3.14159 * 3 * 24 =
</span></span>
<span>
<span>
<span>
452.39 cubic inches which is the lateral area.</span></span></span>
Answer:
The value of x is ![53\°](https://tex.z-dn.net/?f=53%5C%C2%B0)
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
Find the measure of arc DF
we know that
The inscribed angle measures half that of the arc comprising
so
![m](https://tex.z-dn.net/?f=m%3COEF%3D%5Cfrac%7B1%7D%7B2%7D%28arc%5C%20DF%29)
we have
![m](https://tex.z-dn.net/?f=m%3COEF%3D32%5C%C2%B0)
substitute
![32\°=\frac{1}{2}(arc\ DF)\\ arc\ DF=64\°](https://tex.z-dn.net/?f=32%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%28arc%5C%20DF%29%5C%5C%20arc%5C%20DF%3D64%5C%C2%B0)
step 2
Find the measure of x
we know that
---> is a semi circle
we have
![arc\ DF=64\°\\ arc\ EF=(2x+10)\°](https://tex.z-dn.net/?f=arc%5C%20DF%3D64%5C%C2%B0%5C%5C%20arc%5C%20EF%3D%282x%2B10%29%5C%C2%B0)
substitute
![64\°+(2x+10)\°=180\°\\ 2x\°=180\°-74\°\\ 2x\°=106\°\\ x=53\°](https://tex.z-dn.net/?f=64%5C%C2%B0%2B%282x%2B10%29%5C%C2%B0%3D180%5C%C2%B0%5C%5C%202x%5C%C2%B0%3D180%5C%C2%B0-74%5C%C2%B0%5C%5C%202x%5C%C2%B0%3D106%5C%C2%B0%5C%5C%20x%3D53%5C%C2%B0)